[已解决]列表推导式语法错误，求助

Python3005

result = ['yes','yes','yes','yes','yes','yes','yes','yes', 'no','no','no','no','no','no','no','no','no','no']
final = ['https' for each in result if each == 'yes' else 'http']

希望用列表推导式把yes变成https，no变成http，这样报错了：SyntaxError: invalid syntax
应该如何写这个推导式？

最佳答案

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hrp

2019-12-23 02:15:34

不带else用你的格式写，带else用下面的格式写

1. result = ['yes','yes','yes','yes','yes','yes','yes','yes', 'no','no','no','no','no','no','no','no','no','no']
   
2. final = ['https' if each == 'yes' else 'http' for each in result]

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hrp

不带else用你的格式写，带else用下面的格式写

1. result = ['yes','yes','yes','yes','yes','yes','yes','yes', 'no','no','no','no','no','no','no','no','no','no']
   
2. final = ['https' if each == 'yes' else 'http' for each in result]

复制代码