[已解决]为什么用remove之后列表只删除前后两个元素

kevinx0126

附上代码


sandwich_orders = ["lisa", "ben", "kevin","alice"]

fished_sandwiches = []

for people in sandwich_orders:
    print("hello " + people)

    print(sandwich_orders)

    sandwich_orders.remove(people)

    print(sandwich_orders)

    sandwich = input("which kind sandwich would you like ?")

    print("i mande your " + sandwich + " sanwich")

    fished_sandwiches.append(sandwich)

    print("you sandwich is finished")

print(fished_sandwiches)
print(sandwich_orders)


输出结果：
hello lisa
['lisa', 'ben', 'kevin', 'alice']
['ben', 'kevin', 'alice']
which kind sandwich would you like ?a
i mande your a sanwich
you sandwich is finished


hello kevin
['ben', 'kevin', 'alice']
['ben', 'alice']
which kind sandwich would you like ?b
i mande your b sanwich
you sandwich is finished


['a', 'b']
['ben', 'alice']

Process finished with exit code 0

最佳答案

月排行榜 / 总排行榜

zltzlt

2020-2-17 21:07:09

remove() 在遍历中使用通常都是陷阱。。

代码帮你改好了：

1. sandwich_orders = ["lisa", "ben", "kevin", "alice"]
   
2. fished_sandwiches = []
   
3. 
   
4. for people in sandwich_orders[:]:
   
5.     print("hello " + people)
   
6.     print(sandwich_orders)
   
7.     sandwich_orders.remove(people)
   
8.     print(sandwich_orders)
   
9.     sandwich = input("which kind sandwich would you like ?")
   
10.     print("i mande your " + sandwich + " sanwich")
    
11.     fished_sandwiches.append(sandwich)
    
12.     print("you sandwich is finished")
    
13. 
    
14. print(fished_sandwiches)
    
15. print(sandwich_orders)

复制代码

跳转到最佳答案楼层

kevinx0126

新手菜鸟求助

zltzlt

remove() 在遍历中使用通常都是陷阱。。

代码帮你改好了：

1. sandwich_orders = ["lisa", "ben", "kevin", "alice"]
   
2. fished_sandwiches = []
   
3. 
   
4. for people in sandwich_orders[:]:
   
5.     print("hello " + people)
   
6.     print(sandwich_orders)
   
7.     sandwich_orders.remove(people)
   
8.     print(sandwich_orders)
   
9.     sandwich = input("which kind sandwich would you like ?")
   
10.     print("i mande your " + sandwich + " sanwich")
    
11.     fished_sandwiches.append(sandwich)
    
12.     print("you sandwich is finished")
    
13. 
    
14. print(fished_sandwiches)
    
15. print(sandwich_orders)

复制代码

kevinx0126

zltzlt 发表于 2020-2-17 21:07
remove() 在遍历中使用通常都是陷阱。。

代码帮你改好了：

谢大佬

一直

1. a = list(range(10))
   
2. i = 0
   
3. for b in a:
   
4.     print('第' +  str(i) + '次循环a剩余的为',a)
   
5.     print('第' +  str(i) + '次循环删除的为' ,b)
   
6.     i +=1
   
7.     a.remove(b)

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英语小白  看的英语比代码都费劲  总结下你的大概是这个意思
我也是初学着有不对的地方 望指出

1. a = list(range(10))
   
2. i = 0
   
3. for b in a[:]:
   
4.     #这里用上a列表的复制  用remove可以达到想要的结果
   
5.     print('第' +  str(i) + '次循环a剩余的为',a)
   
6.     print('第' +  str(i) + '次循环删除的为' ,b)
   
7.     i +=1
   
8.     a.remove(b)
   

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