[已解决]COVID_19 的统计

dragov

如何输出为：河东区和河北区是重灾区，南开区和和平区是一般区，河西区和红桥区是轻灾区

1. COVID_19 = dict(zip(["河东区","河北区","河西区","南开区","红桥区","和平区"],[15,12,4,6,2,6] ))
   
2. list1=[ ] ;list2=[ ] ;list3=[ ]
   
3. for i in COVID_19:
   
4.     if COVID_19[i] > 10:
   
5.         list1 = COVID_19[i]
   
6.     elif COVID_19[i] < 5:
   
7.         list2 = COVID_19[i]
   
8.     else:
   
9.         list3 = COVID_19[i]
   
10. print( "{0},{1},{2}是新冠肺炎的重灾区、轻灾区、一般区".format(list1,list2,list3))
    

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最佳答案

月排行榜 / 总排行榜

XiaoPaiShen

2020-2-25 03:20:03

1. COVID_19 = dict(zip(["河东区","河北区","河西区","南开区","红桥区","和平区"],[15,12,4,6,2,6] ))
   
2. zz, qz, yb = [], [], []
   
3. 
   
4. for key in COVID_19:
   
5.     if COVID_19[key] > 10:
   
6.         zz.append(key)
   
7.     elif COVID_19[key] < 5:
   
8.         qz.append(key)
   
9.     else:
   
10.         yb.append(key)
    
11. 
    
12. print( "{0}是新冠肺炎的重灾区".format('和'.join(zz)), end=', ')
    
13. print( "{0}是新冠肺炎的一般区".format('和'.join(yb)), end=', ')
    
14. print( "{0}是新冠肺炎的轻灾区".format('和'.join(qz)))

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跳转到最佳答案楼层

拉了盏灯

你可以把地点和人数zip成字典，比较value来分类，
最后在按照值来输出，

XiaoPaiShen

1. COVID_19 = dict(zip(["河东区","河北区","河西区","南开区","红桥区","和平区"],[15,12,4,6,2,6] ))
   
2. zz, qz, yb = [], [], []
   
3. 
   
4. for key in COVID_19:
   
5.     if COVID_19[key] > 10:
   
6.         zz.append(key)
   
7.     elif COVID_19[key] < 5:
   
8.         qz.append(key)
   
9.     else:
   
10.         yb.append(key)
    
11. 
    
12. print( "{0}是新冠肺炎的重灾区".format('和'.join(zz)), end=', ')
    
13. print( "{0}是新冠肺炎的一般区".format('和'.join(yb)), end=', ')
    
14. print( "{0}是新冠肺炎的轻灾区".format('和'.join(qz)))

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