[已解决]查看网页元素，不知道怎么定位到链接

冷冰

如图所示，不知道怎样定位到该链接，求各位大佬帮帮忙，越详细越好，谢谢

最佳答案

月排行榜 / 总排行榜

wp231957

2020-2-25 00:04:07

import requests
from lxml import etree


if __name__ == '__main__':
    url="http://live.500.com/"
    headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.103 Safari/537.36'}
    response = requests.post(url,headers=headers) 
    response.encoding="gb2312" 
    res = etree.HTML(response.text)  
    href = res.xpath("//td[@align='center']/a/@href")
    print(href[0])
   

跳转到最佳答案楼层

wp231957

import requests
from lxml import etree


if __name__ == '__main__':
    url="http://live.500.com/"
    headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/73.0.3683.103 Safari/537.36'}
    response = requests.post(url,headers=headers) 
    response.encoding="gb2312" 
    res = etree.HTML(response.text)  
    href = res.xpath("//td[@align='center']/a/@href")
    print(href[0])
   

EthanHsiung

以BeautifulSoup为例，假设变量a是定位到标签<a>的，a['href']就行了

冷冰

wp231957 发表于 2020-2-25 08:53

谢谢你，但我复制了还有问题，我再改下，要是不行，再求助