[已解决]用dictionary来做七段显示器的问题

hnldyxx551

我已经写好了dictionary
seven_segment = {'0': {'a','c','d','e','b','f'},
'1': {'c','b'},
'2': {'a','d','e','b','g'},
'3': {'a','c','d','b','g'},
'4': {'g','c','f','b'},
'5': {'a','c','d','g','f'},
'6': {'a','c','d','e','g','f'},
'7': {'a','c','b'},
'8': {'a','c','d','e','b','g','f'},
'9': {'a','c','d','b','g','f'}}
题目的要求是有些灯坏了。所以在我输入
>>> guess_character(seven_segment, 'abed')
{'2', '8', '0'}
>>> guess_character(seven_segment, 'a')
{'5', '7', '6', '0', '3', '9', '2', '8'}
>>> guess_character(seven_segment, 'abcdefg')
{'8'}
我的code是这样子的：
def guess_character(display, state):
        query = set(seven_segment)
        candidate_set = {'1','2','3','4','5','6','7','8','9','0'}
        for i in query:
                try:
                        candidate_set = candidate_set & seven_segment[i]
                except:
                        candidate_set = candidate_set
        print(candidate_set)
        return candidate_set

最佳答案

月排行榜 / 总排行榜

冬雪雪冬

2020-3-14 21:44:07

1. def guess_character(seven_segment, string):
   
2.     result = set()
   
3.     set1 = set(string)
   
4.     for n, s in seven_segment.items():
   
5.         if set1 <= s:
   
6.             result.add(n)
   
7.     return result

复制代码

跳转到最佳答案楼层

冬雪雪冬

1. def guess_character(seven_segment, string):
   
2.     result = set()
   
3.     set1 = set(string)
   
4.     for n, s in seven_segment.items():
   
5.         if set1 <= s:
   
6.             result.add(n)
   
7.     return result

复制代码

hnldyxx551

不知道哪里可以改