one problem.

cool121

#include <stdio.h>
void main ()
{
   int i=0;
   printf("Please inuput your grade:");
   scanf("&d",&i);
   if(i>=90&&i<=100)
               printf("Very Good! Your got A!\n",i);
   else if (i<90&&i>=80)
               printf("well, Still Good!It's a B.\n",i);
   else if (i<80&&i>=70)
               printf("good.C\n",i);
   else if (i<70&&i>=60)
               printf("Good LUck! U got a D.\n",i);
   else printf("Sorry, U lost again!\n",i);

}
not work out? :time:

hkcx3000

What's this?----------->scanf("&d",&i);

莫名其妙

My English is not good with the Chinese answer

int i=0;
scanf("&d",&i);   数据要用%d   
   if(i>=90&&i<=100)
               printf("Very Good! Your got A!\n",i);   
else if (i<90&&i>=80)
               printf("well, Still Good!It's a B.\n",i);   
else if (i<80&&i>=70)
               printf("good.C\n",i);
  else if (i<70&&i>=60)
               printf("Good LUck! U got a D.\n",i);
  else printf("Sorry, U lost again!\n",i);
这些 i 是什么意思?    你如果只需要输出语句 不需要输出你上面输入的数据的话后面的i 不能写.
要不就写成printf("******%d***",i); 这种输出语句和i的值
而且你上面还给i 赋了初值 i=0 然后又 scanf() 输入i .

cool121

Sorry, just install the Linux Ubuntu, not install the Chinese input yet. Only can type English now.
But thanks so much for reply.
要不就写成printf("******%d***",i)  This is the one I get wrong.  I change it "&" to "%" .
Then it is OK now.
Thanks for everyone here.

surongre

cool121 发表于 2012-4-6 09:08

                               
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Sorry, just install the Linux Ubuntu, not install the Chinese input yet. Only can type English now.
...

还好看明白你说什么了，我记得ubuntu有中文输入法啊，默认就有的。难道你下载的是英文版的ubuntu？

cool121

yep. I wanna learn English and the Linux system,