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发表于 2020-5-5 20:10:28
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本楼为最佳答案
- #if 0
- By Cool_Breeze
- Dev-C++ 5.11
- x.c
- #endif
-
- #include <stdio.h>
- #include <string.h>
- void sawp(float* p1, float* p2,short len);
- int main(void)
- {
- static float Achievement[300][5];
- //0学号,1语文,2数学,3英语,4三科总和;
- short n=0;
- scanf("%d",&n);
- getchar();
- register short i=0;
- for (i=0;i<n;i++)
- {
- Achievement[i][0]=i+1;
- scanf("%f %f %f",&Achievement[i][1],&Achievement[i][2],&Achievement[i][3]);
- getchar();
- Achievement[i][4]=Achievement[i][1]+Achievement[i][2]+Achievement[i][3];
- }
- //sort
- register short j=0;
- for (i=0;i<n-1;i++)
- for (j=i+1;j<n;j++)
- {
- if (Achievement[j][4] > Achievement[i][4])
- {
- sawp(&Achievement[i][0],&Achievement[j][0],5);
- continue;
- }
- else if (Achievement[j][4] == Achievement[i][4])//总成绩相等
- {
- if (Achievement[j][1] == Achievement[i][1])//语文相等
- {
- if (Achievement[j][0] > Achievement[i][0])// 比较学号
- sawp(&Achievement[i][0],&Achievement[j][0],5);
- continue;
- }
- else if (Achievement[j][1] > Achievement[i][1])
- {
- sawp(&Achievement[i][0],&Achievement[j][0],5);
- continue;
- }
- }
- }
-
-
- for (i=0;i<5;i++)//前5名
- printf("%f %f\n",Achievement[i][0],Achievement[i][4]);
- return 0;
- }
- void sawp(float* p1, float* p2,short len)
- {
- register float t=0;
- for (;len>0;p1++,p2++,len--)
- t=*p1,*p1=*p2,*p2=t;
- }
复制代码- 6
- 90 67 80
- 87 66 91
- 78 89 91
- 88 99 77
- 67 89 64
- 78 89 98
- 6.000000 265.000000
- 4.000000 264.000000
- 3.000000 258.000000
- 2.000000 244.000000
- 1.000000 237.000000
- --------------------------------
- Process exited after 11.32 seconds with return value 0
- 请按任意键继续. . .
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