用python写出的三个效率应用

曲速飞跃 · 发表于 2020-8-11 20:14:05

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通过2周的课余时间编写
终于将他们搞出来了！
我把这三个应用称为CityMorning Tools

第一个应用：TenCat密码记忆工具。
本应用基于对我前面发的账号密码工具
进行了部分的修改与升级

部分代码：

#曲速飞跃作
#请提前在保存此代码的地方创建1.txt
import easygui as g
a = open('1.txt')
b = a.read()
e = int(b)
if e == 1:
d = g.enterbox('查看密码？')
h = int(d)
c = open('mimas.txt')
k = c.read()
f = int(k)
if h != f:
d = g.enterbox('再次输入查看密码？')
h = int(d)
c = open('mimas.txt')
k = c.read()
f = int(k)
if h != f:
exit(0)
while True:
choices = g.buttonbox('主页',title = '密码工具',image = 'TenCat.jpg',choices = ('我的账号密码','增加账号密码','设置','退出'))
if choices == '增加账号密码':
msg = '增加'
title = '密码工具'
table = g.enterbox('平台？')
name = g.enterbox('账号？')
message = g.enterbox('密码？')
mes = message + "I LOVE STUDY 0962135 qusufeiyuezuo"
with open('pingtai.txt', 'a+') as f:
f.write(str(table))
f.write('\r\n')
with open('zhanghao.txt', 'a+') as f:
f.write(str(name))
f.write('\r\n')
with open('mima.txt', 'a+') as f:
f.write(str(mes))
f.write('\r\n')
elif choices == '我的账号密码':
a = open('pingtai.txt')
pt = a.read()
c = open('zhanghao.txt')
zh = c.read()
e = open('mima.txt')
message = e.read()
First = message
Second = "I LOVE STUDY 0962135 qusufeiyuezuo"
end = ""
for i in First:
if i in Second:
First = First.replace(i, "")
g.msgbox('平台：' + pt + '账号：' + zh + '密码：' + First )
elif choices == '设置':
msg = '设置'
title = '密码工具'
choices = ['使用说明','删除账号密码','设置查看密码']
choices = g.choicebox(msg, title, choices)
if choices == '使用说明':
g.msgbox('这个工具用于帮助记不住密码的人。点击增加账号密码可增加，点击我的账号密码即可查询。在设置-设置查看密码可以设置密码。')
elif choices == '删除账号密码':
g.msgbox('在此程序保存的位置找到pingtai.txt，zhanghao.txt，mima.txt，删除对应信息即可。')
elif choices == '设置查看密码':
mima = g.enterbox('密码？(数字)')
with open('mimas.txt', 'w') as f:
f.write(str(mima))
with open('1.txt', 'w') as f:
f.write(str(1))
elif choices == '退出':
exit(0)

复制代码

请保存：
链接: https://pan.baidu.com/s/1zUOkK_m4hFXA7cXIwaz0ww
提取码: 9dky

第二个应用：DoIt待办事项
这是一个非常非常简单的待办应用
以后会慢慢完善的
部分代码：

#曲速飞跃作
import easygui as g
import random
a = open('1.txt')
b = a.read()
e = int(b)
if e == 1:
d = g.enterbox('查看密码？')
h = int(d)
c = open('mimas.txt')
k = c.read()
f = int(k)
if h != f:
d = g.enterbox('再次输入查看密码？')
h = int(d)
c = open('mimas.txt')
k = c.read()
f = int(k)
if h != f:
exit(0)
while True:
a = open("doit.txt")
b = a.read()
k = str(b)
se = random.randint(1, 5)
if se == 1:
ss = "\n\n\n\n\n书山有路勤为径，学海无涯苦作舟。"
elif se == 2:
ss = "\n\n\n\n\n读书破万卷，下笔如有神。"
elif se == 3:
ss = "\n\n\n\n\n少壮不努力，老大徒伤悲。"
elif se == 4:
ss = "\n\n\n\n\nI love study,study makes me happy!"
elif se == 5:
ss = "\n\n\n\n\n三更灯火五更鸡，正是男儿读书时。"
if k == "":
num = "任务都完成啦！" + ss
else:
num = "今日还有任务呢！加油鸭！" + ss
c = g.buttonbox(num + "\n\n\n\n\n",title="DoIt",image = "DoIt.jpg",choices=("我的待办","增加待办","设置","退出"))
if c == "增加待办":
enter = g.enterbox("待办名称？")
with open('doit.txt', 'a+') as f:
f.write(str(enter))
f.write('\r\n')
g.msgbox("设置成功！")
elif c == "我的待办":
a = open("doit.txt")
b = a.read()
c = str(b)
msg = c
title = "DoIt"
choice2 = ["我看到了","标记全部完成"]
c2 = g.buttonbox(msg,title,choice2)
if c2 == "我看到了":
g.msgbox("那还不赶快完成！？")
else:
with open('doit.txt', 'w') as f:
f.write("")
elif c == "设置":
msg = "设置"
title = "DoIt"
choice3 = ["设置开始密码","更新信息"]
c3 = g.choicebox(msg,title,choice3)
if c3 == "设置开始密码":
mima = g.enterbox('密码？(数字)')
with open('mimas.txt', 'w') as f:
f.write(str(mima))
with open('1.txt', 'w') as f:
f.write(str(1))
else:
g.msgbox("该版本为1.0.0，为初始版本！")
elif c == "退出":
exit(0)

复制代码

请保存：
链接: https://pan.baidu.com/s/1fmOyVO7NzARZMcloPmmaNA
提取码: r63v

第三个应用：重头戏 TurtleTomato番茄工作法
一样的，很简陋，以后慢慢补充
部分代码：

#曲速飞跃作
import easygui as g
import random
import time
from tkinter import *
a = open('1.txt')
b = a.read()
e = int(b)
if e == 1:
d = g.enterbox('查看密码？')
h = int(d)
c = open('mimas.txt')
k = c.read()
f = int(k)
if h != f:
d = g.enterbox('再次输入查看密码？')
h = int(d)
c = open('mimas.txt')
k = c.read()
f = int(k)
if h != f:
exit(0)
while True:
se = random.randint(1, 5)
if se == 1:
ss = "\n\n\n\n\n书山有路勤为径，学海无涯苦作舟。"
elif se == 2:
ss = "\n\n\n\n\n读书破万卷，下笔如有神。"
elif se == 3:
ss = "\n\n\n\n\n少壮不努力，老大徒伤悲。"
elif se == 4:
ss = "\n\n\n\n\nI love study,study makes me happy!"
elif se == 5:
ss = "\n\n\n\n\n三更灯火五更鸡，正是男儿读书时。"
c1 = g.buttonbox("TurtleTomato 番茄工作法" + ss,title="TurtleTomato",image = "TurtleTomato.jpg",choices= ("开始番茄","番茄统计","历史记录","设置","退出"))
if c1 == "开始番茄":
do = g.enterbox("您要专注于？")
t = g.enterbox("时长？(一般25分钟）")
tt = int(t)
ttt = tt * 60
import pygame
import sys
from pygame.locals import *
pygame.mixer.init()
pygame.mixer.music.load("chanchanchan.ogg")
pygame.mixer.music.play()
for i in range(ttt + 1):
print(ttt - i)
time.sleep(1)
pygame.mixer.music.stop()
msg = "恭喜你完成专注（" + str(tt) + "分钟）！"
title = "TurtlrTomato"
choice = ["完成"]
c4 = g.buttonbox(msg,title,choice)
if c4 == "完成":
import datetime
nowTime = datetime.datetime.now().strftime('%Y-%m-%d %H:%M:%S')
with open('history.txt', 'a+') as f:
f.write(str(nowTime) + str(do) + str(tt) + "分钟")
f.write('\r\n')
with open('time.txt','a+') as f:
f.write("1")
msg = "是否休息？"
title = "TurtleTomato"
cho = ["是","否"]
c6 = g.buttonbox(msg,title,cho)
if c6 == "是":
pygame.mixer.music.play()
for i in range(301):
print(301 - i)
time.sleep(1)
pygame.mixer.music.stop()
g.msgbox("继续干起来！")
elif c1 == "历史记录":
a = open("history.txt")
b = a.read()
g.msgbox(b)
elif c1 == "退出":
exit(0)
elif c1 == "设置":
msg = "设置"
title = "TurtleTomato"
choice5 = ["设置开始密码","版本信息","番茄工作法"]
c5 = g.buttonbox(msg,title,choice5)
if c5 == "设置开始密码":
mima = g.enterbox('密码？(数字)')
with open('mimas.txt', 'w') as f:
f.write(str(mima))
with open('1.txt', 'w') as f:
f.write(str(1))
elif c5 == "版本信息":
g.msgbox("1.0.0")
elif c5 == "番茄工作法":
g.msgbox("番茄工作法是简单易行的时间管理方法.使用番茄工作法，选择一个待完成的任务，将番茄时间设为25分钟，专注工作，中途不允许做任何与该任务无关的事，直到番茄时钟响起，然后进行短暂休息一下（5分钟就行），然后再开始下一个番茄。每4个番茄时段多休息一会儿。番茄工作法极大地提高了工作的效率，还会有意想不到的成就感。")
elif c1 == "番茄统计":
a = open('time.txt')
b = a.read()
time = len(b)
g.msgbox("您一共专注了" + str(time) + "次！")

复制代码

请保存：
链接: https://pan.baidu.com/s/1SP5GTobGgG5ViFSz0ajNFA
提取码: j7jb

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[作品展示] 用python写出的三个效率应用

马上注册，结交更多好友，享用更多功能^_^