|
马上注册,结交更多好友,享用更多功能^_^
您需要 登录 才可以下载或查看,没有账号?立即注册
x
我自己写的答案觉得逻辑没啥问题,但是结果差了零点零几
并且我复制过来的代码运行的结果与题目应得的结果也不一样,也是差了零点零几
这是为什么呢?
求大佬解答,感激不尽
ps:我用的devc++,在Windows上运行的
答案给的代码:
- #include <stdio.h>
- #include <math.h>
- int main()
- {
- float price, area, yir, mir; // 单价、面积、年利率、月利率
- float interest, loan; // 利息、贷款总额
- float ave_repay, down_payment; // 月均还款、首期付款
- float total_price, total_repay; // 房款总额、还款总额
- int ratio, time; // 按揭成数、按揭年数
- printf("请输入单价(元/平方):");
- scanf("%f", &price);
- printf("请输入面积:");
- scanf("%f", &area);
- printf("请输入按揭成数:");
- scanf("%d", &ratio);
- printf("请输入按揭年数:");
- scanf("%d", &time);
- printf("请输入当前基准年利率:");
- scanf("%f", &yir);
- mir = yir / 100 / 12; // 年利率需要除以100得到,因为用户输入是5.4(%),而不是0.054
- time = time * 12;
- total_price = price * area;
- loan = total_price * ratio / 10; // 这里不能写成(ratio / 10),否则结果会变成0
- ave_repay = loan * mir * pow((1 + mir), time) / (pow((1 + mir), time) - 1);
- interest = ave_repay * time - loan;
- total_repay = loan + interest;
- down_payment = total_price * (1 - (float)ratio / 10); // 强制转换ratio为浮点型
- printf("========== 报告结果 ==========\n");
- printf("房款总额:%.2f元\n", total_price);
- printf("首期付款:%.2f元\n", down_payment);
- printf("贷款总额:%.2f元\n", loan);
- printf("还款总额:%.2f元\n", total_repay);
- printf("支付利息:%.2f元\n", interest);
- printf("月均还款:%.2f元\n", ave_repay);
- return 0;
- }
复制代码
我的运行结果:
房款总额:720000.00元
首期付款:216000.02元
贷款总额:504000.00元
还款总额:825248.44元
支付利息:321248.44元
月均还款:3438.54元
题目上的结果:
如图所示
自己写的代码:
- #include <stdio.h>
- #include <math.h>
- int main()
- {
- float price, area, yir, mir;
- float interest, loan;
- float ave_repay, down_payment;
- float total_price, total_repay;
- int ratio, time;
-
- printf("请输入单价(元/平方):");
- scanf("%f", &price);
- printf("请输入面积:");
- scanf("%f", &area);
- printf("请输入按揭成数:");
- scanf("%d", &ratio);
- printf("请输入按揭年数:");
- scanf("%d", &time);
- printf("请输入当前基准年利率:");
- scanf("%f", &yir);
-
- total_price = area * price;
- down_payment = (10 - ratio) * 0.1 * total_price;
- loan = total_price - down_payment;
- mir = yir / 12;
- ave_repay = loan * ((mir/100) * pow((1 + mir/100), (12 * time)))/( pow((1 + mir/100) ,(12 * time) )-1);
- total_repay = time * 12 * ave_repay;
- interest = total_repay - loan;
-
-
- printf("==========报告结果==========\n");
- printf("房款总额:%.2f元\n", total_price);
- printf("首期付款:%.2f元\n", down_payment);
- printf("贷款总额:%.2f元\n", loan);
- printf("还款总额:%.2f元\n", total_repay);
- printf("支付利息:%.2f元\n", interest);
- printf("月均还款:%.2f元\n", ave_repay);
- printf("");
-
- return 0;
-
-
- }
复制代码
运行结果:
房款总额:720000.00元
首期付款:216000.00元
贷款总额:504000.00元
还款总额:825248.38元
支付利息:321248.38元
月均还款:3438.53元
使用pow函数里面参数定义为double类型的好,要不容易出现精度损失
|
-
|