[已解决]分支循环作业题

幻树师

看不懂这个错，求解
num = int(input("请输入今年的利润:"))

if num <= 100000:
    reward = num*(0.1)

  
elif 100000 < num <= 200000:

    reward = 100000*0.1 +(num - 100000)* (0.075)
   
elif 200000 < num <= 400000:
   
    reward = 100000*0.1 + 100000*0.075 +(num - 200000)* (0.05)

elif 400000 < num <= 600000:
    reward = 100000*0.1 + 100000*0.075 + 200000*0.05 +(num - 400000)* (0.03)
elif 600000 < num <= 1000000:
   
    reward =(100000*0.1 + 100000*0.075  + 200000*0.05 + 200000*0.03 +(num - 600000)* (0.015)
else:
   
    reward = 100000*0.1 + 100000*0.075  + 200000*0.05 + 200000*0.03 + 400000*0.015 +(num - 1000000)* (0.01)
   
   
print("应该发放的奖金总数是: ",reward,sep='')

最佳答案

月排行榜 / 总排行榜

baige

2020-9-22 23:10:05

else上一行后面少了个)

跳转到最佳答案楼层

baige

else上一行后面少了个)

昨非

1. 
   
2. num = int(input("请输入今年的利润:"))
   
3. 
   
4. if num <= 100000:
   
5.     reward = num*(0.1)
   
6. 
   
7. elif 100000 < num <= 200000:
   
8.     reward = 100000*0.1 +(num - 100000)* (0.075)
   
9.    
   
10. elif 200000 < num <= 400000:
    
11.     reward = 100000*0.1 + 100000*0.075 +(num - 200000)* (0.05)
    
12. 
    
13. elif 400000 < num <= 600000:
    
14.     reward = 100000*0.1 + 100000*0.075 + 200000*0.05 +(num - 400000)* (0.03)
    
15. 
    
16. elif 600000 < num <= 1000000:   
    
17.     reward =(100000*0.1 + 100000*0.075  + 200000*0.05 + 200000*0.03 +(num - 600000)* (0.015))
    
18. 
    
19. else:
    
20.     reward = 100000*0.1 + 100000*0.075  + 200000*0.05 + 200000*0.03 + 400000*0.015 +(num - 1000000)* (0.01)
    
21.       
    
22. print("应该发放的奖金总数是: ",reward,sep='')
    

复制代码

昨非

baige 发表于 2020-9-22 23:10
else上一行后面少了个)

抱歉没看到已经回复了

幻树师

baige 发表于 2020-9-22 23:10
else上一行后面少了个)

谢谢

幻树师

昨非 发表于 2020-9-22 23:11

谢谢