Leetcode 239. Sliding Window Maximum

Seawolf

You are given an array of integers nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window. Each time the sliding window moves right by one position.

Return the max sliding window.



Example 1:

Input: nums = [1,3,-1,-3,5,3,6,7], k = 3
Output: [3,3,5,5,6,7]
Explanation:
Window position                Max
---------------               -----
[1  3  -1] -3  5  3  6  7       3
1 [3  -1  -3] 5  3  6  7       3
1  3 [-1  -3  5] 3  6  7       5
1  3  -1 [-3  5  3] 6  7       5
1  3  -1  -3 [5  3  6] 7       6
1  3  -1  -3  5 [3  6  7]      7
Example 2:

Input: nums = [1], k = 1
Output: [1]
Example 3:

Input: nums = [1,-1], k = 1
Output: [1,-1]
Example 4:

Input: nums = [9,11], k = 2
Output: [11]
Example 5:

Input: nums = [4,-2], k = 2
Output: [4]


Constraints:

1 <= nums.length <= 105
-104 <= nums <= 104
1 <= k <= nums.length

1. from collections import deque
   
2. class Solution:
   
3.     def maxSlidingWindow(self, nums: List[int], k: int) -> List[int]:
   
4.         queue = deque()
   
5.         res = []
   
6.         if len(nums) == 0:
   
7.             return res
   
8.         for i in range(k - 1):
   
9.             self.indeque(queue, nums[i])
   
10.         for i in range(k - 1, len(nums)):
    
11.             self.indeque(queue, nums[i])
    
12.             res.append(queue[0])
    
13.             self.outdeque(queue, nums[i - k + 1])
    
14.         return res
    
15.    
    
16.     def indeque(self, queue: List[int], num: int) -> None:
    
17.         while len(queue) != 0 and queue[-1] < num:
    
18.             queue.pop()
    
19.         queue.append(num)
    
20.    
    
21.     def outdeque(self, queue: List[int], num: int) -> None:
    
22.         if queue[0] == num:
    
23.             queue.popleft()

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