[已解决]将多位整数转成列表

jtxs0000

1. # 第一个问题
   
2. # nums = [2,5,3,8]
   
3. 
   
4. # 输出为：[5,5,8,8,8]  2个5，3个8
   
5. 
   
6. 
   
7. # # 第二个问题
   
8. # nums = [42,39]       
   
9. # 输出为：[39,39,39,39,39,39,39,39,39,39,39,39,39......]   一共42个39
   
10. 
    

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第一个基本会做了，但用第一个的代码运行第二个会先显示

1. ['3', '9', '3', '9', '3', '9', '3', '9', '3', '9', '3', '9', '3', '9']

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有没有大佬会这个的

最佳答案

月排行榜 / 总排行榜

疾风怪盗

2020-10-13 15:15:25

jtxs0000 发表于 2020-10-13 15:07
好吧，应该是我没有描述清楚，我是想要写一组代码，能把第一个问题和第二个问题都能运行起来，甚至说，如 ...

这样？

1. nums = [42,39,12,5,100,23]
   
2. new=[nums[i+1] for i in range(0,len(nums),2) for a in range(1,nums[i]+1)]
   
3. print(new)

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[39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23]

跳转到最佳答案楼层

冬雪雪冬

1. >>> nums = [42,39]
   
2. >>> print([nums[1]] * nums[0])
   
3. [39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39]

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jtxs0000

冬雪雪冬 发表于 2020-10-13 15:03

好吧，应该是我没有描述清楚，我是想要写一组代码，能把第一个问题和第二个问题都能运行起来，甚至说，如果出现其他类似的也可以运行，比如

1. nums = [42,39，12，5，100，23]

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疾风怪盗

jtxs0000 发表于 2020-10-13 15:07
好吧，应该是我没有描述清楚，我是想要写一组代码，能把第一个问题和第二个问题都能运行起来，甚至说，如 ...

这样？

1. nums = [42,39,12,5,100,23]
   
2. new=[nums[i+1] for i in range(0,len(nums),2) for a in range(1,nums[i]+1)]
   
3. print(new)

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[39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 39, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23]

冬雪雪冬

jtxs0000 发表于 2020-10-13 15:07
好吧，应该是我没有描述清楚，我是想要写一组代码，能把第一个问题和第二个问题都能运行起来，甚至说，如 ...

1. nums = [42, 39, 12, 5, 100, 23]
   
2. output = []
   
3. for each in range(0, len(nums), 2):
   
4.     output += nums[each] * [nums[each + 1]]
   
5. print(output)

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伪文青

1. num = [5,3,2,4,2,8]
   
2. l = len(num)
   
3. nums = []
   
4. if l%2==0:
   
5.     #偶数输出列表
   
6.     for i in range(0,l):
   
7.         if i%2!=0:
   
8.             nums.extend([num[i]] * num[i-1])
   
9. else:
   
10.     #奇数报错
    
11.     print("少一个数字")
    
12. print(nums)

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