set的回顾

gzj137070928

set集合具有唯一性，无序性，所以没有索引index
frozenset（）用来限制集合的修改

set1 = frozenset([1, 2, 3, 5])
set2 = {1, 3, 2, 5}
print(set1 == set2)
# 下面则不可创建集合
try:
    set3 = {[1, 2, 3, 5]}
except Exception as e:
    print(e)
try:
    set1.add(4)  # set1不可变更
except Exception as e1:
    print(e1)
set2.add(8)
set2.remove(3)
print(set2)
set4 = {1, 1.0}
print(set4)