set的回顾

gzj137070928

set集合具有唯一性，无序性，所以没有索引index
frozenset（）用来限制集合的修改

1. set1 = frozenset([1, 2, 3, 5])
   
2. set2 = {1, 3, 2, 5}
   
3. print(set1 == set2)
   
4. # 下面则不可创建集合
   
5. try:
   
6.     set3 = {[1, 2, 3, 5]}
   
7. except Exception as e:
   
8.     print(e)
   
9. try:
   
10.     set1.add(4)  # set1不可变更
    
11. except Exception as e1:
    
12.     print(e1)
    
13. set2.add(8)
    
14. set2.remove(3)
    
15. print(set2)
    
16. set4 = {1, 1.0}
    
17. print(set4)

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