[已解决]爬虫，百度翻译

qin_yin

import requests
import json
url = 'https://fanyi.baidu.com/sug'
headers = {
    'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/87.0.4280.66 Safari/537.36'
    }

work = input('请输入需要翻译的关键词')
data = {'kw':work}
response = requests.post(url=url,data=data,headers=headers)
a = response.json()
print(a)
print(json.dumps(a,ensure_ascii=False,sort_keys=True))

请输入需要翻译的关键词cat
{'errno': 0, 'data': [{'k': 'cat ear', 'v': '[医]猫耳'}, {'k': 'cat fur', 'v': '[医]猫皮毛'}, {'k': 'cat nap', 'v': 'n. 打瞌睡'}, {'k': 'cat eyes', 'v': '猫眼'}, {'k': 'cat fish', 'v': '[医]鲶（鱼），鲇鱼'}]}
{"data": [{"k": "cat ear", "v": "[医]猫耳"}, {"k": "cat fur", "v": "[医]猫皮毛"}, {"k": "cat nap", "v": "n. 打瞌睡"}, {"k": "cat eyes", "v": "猫眼"}, {"k": "cat fish", "v": "[医]鲶（鱼），鲇鱼"}], "errno": 0}

我想问为什么这里没有一个我想要的结果，

最佳答案

月排行榜 / 总排行榜

suchocolate

2020-11-21 10:53:31

这个sug url只能翻译单个字，翻译有另外的url:https://fanyi.baidu.com/v2transapi，且还需要提交sign和token，你可以参考下这个：https://blog.csdn.net/qq_38534107/article/details/90440403，以下是参考他的方法写的代码：

1. 
   
2. import execjs
   
3. import requests
   
4. 
   
5. 
   
6. class BaiduTranslateJS:
   
7.     def __init__(self):
   
8.         self.url = "https://fanyi.baidu.com/v2transapi"
   
9.         self.headers = {
   
10.             "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:66.0) Gecko/20100101 Firefox/66.0",
    
11.             "Cookie": "BAIDUID=F0E3DE0018AFB4C172AD6D2E7C917128:FG=1; BIDUPSID=F0E3DE0018AFB4C1DFC82BD817EAC44D; "
    
12.                       "PSTM=1595323520; MCITY=-%3A; "
    
13.                       "BDUSS=IxVFNzRlJ0b1VhcWVWS3VLV1dwLVpRdmNMY01ZMUtxM2RGblBPanVZV3pHV2RmSVFBQUFBJCQAAAAAAAAAAAEAAA"
    
14.                       "AQTRwgQ3JpdGljMjAxMgAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAALOMP"
    
15.                       "1-zjD9fa1; BDORZ=B490B5EBF6F3CD402E515D22BCDA1598; Hm_lvt_64ecd82404c51e03dc91cb9e8c025574=16059"
    
16.                       "21866,1605929186; REALTIME_TRANS_SWITCH=1; FANYI_WORD_SWITCH=1; HISTORY_SWITCH=1; SOUND_SPD_SWI"
    
17.                       "TCH=1; SOUND_PREFER_SWITCH=1; yjs_js_security_passport=01bd0488dc53c6663e9038c21110dd20eaa3d83"
    
18.                       "e_1605929187_js; BA_HECTOR=a080alal0501a02h1e1frh03m0q; __yjsv5_shitong=1.0_7_3d669e2415c752e931"
    
19.                       "566ddcdfe31f01a9af_300_1605929186447_112.1.222.242_a0e2999e; Hm_lpvt_64ecd82404c51e03dc91cb9e8c"
    
20.                       "025574=1605929186 "
    
21.         }
    
22.         self.data = {
    
23.             "from": "zh",
    
24.             "to": "en",
    
25.             "query": "",
    
26.             "simple_means_flag": "3",
    
27.             "sign": "",
    
28.             "token": "5a3db26d59330f426a3c74eca9c27a27",   #  token获取方法见下面
    
29.             "domain": "common"
    
30.         }
    
31. 
    
32.     def t(self, query):
    
33.         self.data['query'] = query
    
34.         with open('test.js', 'r', encoding='utf-8') as f:
    
35.             ctx = execjs.compile(f.read())
    
36.         sign = ctx.call('e', query)
    
37.         self.data['sign'] = sign
    
38.         r = requests.post(self.url, headers=self.headers, data=self.data)
    
39.         rj = r.json()
    
40.         # print(rj)
    
41.         r_x = rj['trans_result']['data'][0]['dst']
    
42.         return r_x
    
43. 
    
44. 
    
45. if __name__ == '__main__':
    
46.     bt = BaiduTranslateJS()
    
47.     result = bt.t('我的家在东北')
    
48.     print(result)

复制代码

token和js里的i值获取方法：

1. import requests
   
2. import re
   
3. 
   
4. 
   
5. def main():
   
6.     url = 'https://fanyi.baidu.com'
   
7.     headers = {'user-agent': 'firefox'}
   
8.     r = requests.get(url, headers=headers)
   
9.     token = re.findall(r"token: '(.*?)',", r.text)[0]
   
10.     print(token)   # token
    
11.     gtk = re.findall(r"gtk = '(.*?)'", r.text)[0]
    
12.     print(gtk)    # js里用的i的值
    
13. 
    
14. 
    
15. if __name__ == '__main__':
    
16.     main()
    

复制代码

官网现在的js照那个笔记有变动，从浏览器拷贝代码，本地新建test.js

1. function n(r, o) {
   
2.   for (var t = 0; t < o.length - 2; t += 3) {
   
3.     var a = o.charAt(t + 2);
   
4.     a = a >= 'a' ? a.charCodeAt(0) - 87 : Number(a),
   
5.     a = '+' === o.charAt(t + 1) ? r >>> a : r << a,
   
6.     r = '+' === o.charAt(t) ? r + a & 4294967295 : r ^ a
   
7.   }
   
8.   return r
   
9. }
   
10. function e(r) {
    
11.   var i = '320305.131321201'
    
12.   var o = r.match(/[\uD800-\uDBFF][\uDC00-\uDFFF]/g);
    
13.   if (null === o) {
    
14.     var t = r.length;
    
15.     t > 30 && (r = '' + r.substr(0, 10) + r.substr(Math.floor(t / 2) - 5, 10) + r.substr( - 10, 10))
    
16.   } else {
    
17.     for (var e = r.split(/[\uD800-\uDBFF][\uDC00-\uDFFF]/), C = 0, h = e.length, f = [
    
18.     ]; h > C; C++) '' !== e[C] && f.push.apply(f, a(e[C].split(''))),
    
19.     C !== h - 1 && f.push(o[C]);
    
20.     var g = f.length;
    
21.     g > 30 && (r = f.slice(0, 10).join('') + f.slice(Math.floor(g / 2) - 5, Math.floor(g / 2) + 5).join('') + f.slice( - 10).join(''))
    
22.   }
    
23.   var u = void 0,
    
24.   l = '' + String.fromCharCode(103) + String.fromCharCode(116) + String.fromCharCode(107);
    
25.   u = null !== i ? i : (i = window[l] || '') || '';
    
26.   for (var d = u.split('.'), m = Number(d[0]) || 0, s = Number(d[1]) || 0, S = [
    
27.   ], c = 0, v = 0; v < r.length; v++) {
    
28.     var A = r.charCodeAt(v);
    
29.     128 > A ? S[c++] = A : (2048 > A ? S[c++] = A >> 6 | 192 : (55296 === (64512 & A) && v + 1 < r.length && 56320 === (64512 & r.charCodeAt(v + 1)) ? (A = 65536 + ((1023 & A) << 10) + (1023 & r.charCodeAt(++v)), S[c++] = A >> 18 | 240, S[c++] = A >> 12 & 63 | 128)  : S[c++] = A >> 12 | 224, S[c++] = A >> 6 & 63 | 128), S[c++] = 63 & A | 128)
    
30.   }
    
31.   for (var p = m, F = '' + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(97) + ('' + String.fromCharCode(94) + String.fromCharCode(43) + String.fromCharCode(54)), D = '' + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(51) + ('' + String.fromCharCode(94) + String.fromCharCode(43) + String.fromCharCode(98)) + ('' + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(102)), b = 0; b < S.length; b++) p += S[b],
    
32.   p = n(p, F);
    
33.   return p = n(p, D),
    
34.   p ^= s,
    
35.   0 > p && (p = (2147483647 & p) + 2147483648),
    
36.   p %= 1000000,
    
37.   p.toString() + '.' + (p ^ m)
    
38. }

复制代码

另外百度翻译免费开放api，申请一下就能用：https://api.fanyi.baidu.com/

跳转到最佳答案楼层

笨鸟学飞

会不会是哪里出问题了？如果你只需要英翻中，可以试试直接get，我的浏览器显示的这样的url
https://fanyi.baidu.com/?aldtype=16047#en/zh/cat
看见没有，这个就很明显了
temp = input('请输入待翻译的英文：')
url = r'https://fanyi.baidu.com/?aldtype=16047#en/zh/'+temp

suchocolate

这个sug url只能翻译单个字，翻译有另外的url:https://fanyi.baidu.com/v2transapi，且还需要提交sign和token，你可以参考下这个：https://blog.csdn.net/qq_38534107/article/details/90440403，以下是参考他的方法写的代码：

1. 
   
2. import execjs
   
3. import requests
   
4. 
   
5. 
   
6. class BaiduTranslateJS:
   
7.     def __init__(self):
   
8.         self.url = "https://fanyi.baidu.com/v2transapi"
   
9.         self.headers = {
   
10.             "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:66.0) Gecko/20100101 Firefox/66.0",
    
11.             "Cookie": "BAIDUID=F0E3DE0018AFB4C172AD6D2E7C917128:FG=1; BIDUPSID=F0E3DE0018AFB4C1DFC82BD817EAC44D; "
    
12.                       "PSTM=1595323520; MCITY=-%3A; "
    
13.                       "BDUSS=IxVFNzRlJ0b1VhcWVWS3VLV1dwLVpRdmNMY01ZMUtxM2RGblBPanVZV3pHV2RmSVFBQUFBJCQAAAAAAAAAAAEAAA"
    
14.                       "AQTRwgQ3JpdGljMjAxMgAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAALOMP"
    
15.                       "1-zjD9fa1; BDORZ=B490B5EBF6F3CD402E515D22BCDA1598; Hm_lvt_64ecd82404c51e03dc91cb9e8c025574=16059"
    
16.                       "21866,1605929186; REALTIME_TRANS_SWITCH=1; FANYI_WORD_SWITCH=1; HISTORY_SWITCH=1; SOUND_SPD_SWI"
    
17.                       "TCH=1; SOUND_PREFER_SWITCH=1; yjs_js_security_passport=01bd0488dc53c6663e9038c21110dd20eaa3d83"
    
18.                       "e_1605929187_js; BA_HECTOR=a080alal0501a02h1e1frh03m0q; __yjsv5_shitong=1.0_7_3d669e2415c752e931"
    
19.                       "566ddcdfe31f01a9af_300_1605929186447_112.1.222.242_a0e2999e; Hm_lpvt_64ecd82404c51e03dc91cb9e8c"
    
20.                       "025574=1605929186 "
    
21.         }
    
22.         self.data = {
    
23.             "from": "zh",
    
24.             "to": "en",
    
25.             "query": "",
    
26.             "simple_means_flag": "3",
    
27.             "sign": "",
    
28.             "token": "5a3db26d59330f426a3c74eca9c27a27",   #  token获取方法见下面
    
29.             "domain": "common"
    
30.         }
    
31. 
    
32.     def t(self, query):
    
33.         self.data['query'] = query
    
34.         with open('test.js', 'r', encoding='utf-8') as f:
    
35.             ctx = execjs.compile(f.read())
    
36.         sign = ctx.call('e', query)
    
37.         self.data['sign'] = sign
    
38.         r = requests.post(self.url, headers=self.headers, data=self.data)
    
39.         rj = r.json()
    
40.         # print(rj)
    
41.         r_x = rj['trans_result']['data'][0]['dst']
    
42.         return r_x
    
43. 
    
44. 
    
45. if __name__ == '__main__':
    
46.     bt = BaiduTranslateJS()
    
47.     result = bt.t('我的家在东北')
    
48.     print(result)

复制代码

token和js里的i值获取方法：

1. import requests
   
2. import re
   
3. 
   
4. 
   
5. def main():
   
6.     url = 'https://fanyi.baidu.com'
   
7.     headers = {'user-agent': 'firefox'}
   
8.     r = requests.get(url, headers=headers)
   
9.     token = re.findall(r"token: '(.*?)',", r.text)[0]
   
10.     print(token)   # token
    
11.     gtk = re.findall(r"gtk = '(.*?)'", r.text)[0]
    
12.     print(gtk)    # js里用的i的值
    
13. 
    
14. 
    
15. if __name__ == '__main__':
    
16.     main()
    

复制代码

官网现在的js照那个笔记有变动，从浏览器拷贝代码，本地新建test.js

1. function n(r, o) {
   
2.   for (var t = 0; t < o.length - 2; t += 3) {
   
3.     var a = o.charAt(t + 2);
   
4.     a = a >= 'a' ? a.charCodeAt(0) - 87 : Number(a),
   
5.     a = '+' === o.charAt(t + 1) ? r >>> a : r << a,
   
6.     r = '+' === o.charAt(t) ? r + a & 4294967295 : r ^ a
   
7.   }
   
8.   return r
   
9. }
   
10. function e(r) {
    
11.   var i = '320305.131321201'
    
12.   var o = r.match(/[\uD800-\uDBFF][\uDC00-\uDFFF]/g);
    
13.   if (null === o) {
    
14.     var t = r.length;
    
15.     t > 30 && (r = '' + r.substr(0, 10) + r.substr(Math.floor(t / 2) - 5, 10) + r.substr( - 10, 10))
    
16.   } else {
    
17.     for (var e = r.split(/[\uD800-\uDBFF][\uDC00-\uDFFF]/), C = 0, h = e.length, f = [
    
18.     ]; h > C; C++) '' !== e[C] && f.push.apply(f, a(e[C].split(''))),
    
19.     C !== h - 1 && f.push(o[C]);
    
20.     var g = f.length;
    
21.     g > 30 && (r = f.slice(0, 10).join('') + f.slice(Math.floor(g / 2) - 5, Math.floor(g / 2) + 5).join('') + f.slice( - 10).join(''))
    
22.   }
    
23.   var u = void 0,
    
24.   l = '' + String.fromCharCode(103) + String.fromCharCode(116) + String.fromCharCode(107);
    
25.   u = null !== i ? i : (i = window[l] || '') || '';
    
26.   for (var d = u.split('.'), m = Number(d[0]) || 0, s = Number(d[1]) || 0, S = [
    
27.   ], c = 0, v = 0; v < r.length; v++) {
    
28.     var A = r.charCodeAt(v);
    
29.     128 > A ? S[c++] = A : (2048 > A ? S[c++] = A >> 6 | 192 : (55296 === (64512 & A) && v + 1 < r.length && 56320 === (64512 & r.charCodeAt(v + 1)) ? (A = 65536 + ((1023 & A) << 10) + (1023 & r.charCodeAt(++v)), S[c++] = A >> 18 | 240, S[c++] = A >> 12 & 63 | 128)  : S[c++] = A >> 12 | 224, S[c++] = A >> 6 & 63 | 128), S[c++] = 63 & A | 128)
    
30.   }
    
31.   for (var p = m, F = '' + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(97) + ('' + String.fromCharCode(94) + String.fromCharCode(43) + String.fromCharCode(54)), D = '' + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(51) + ('' + String.fromCharCode(94) + String.fromCharCode(43) + String.fromCharCode(98)) + ('' + String.fromCharCode(43) + String.fromCharCode(45) + String.fromCharCode(102)), b = 0; b < S.length; b++) p += S[b],
    
32.   p = n(p, F);
    
33.   return p = n(p, D),
    
34.   p ^= s,
    
35.   0 > p && (p = (2147483647 & p) + 2147483648),
    
36.   p %= 1000000,
    
37.   p.toString() + '.' + (p ^ m)
    
38. }

复制代码

另外百度翻译免费开放api，申请一下就能用：https://api.fanyi.baidu.com/