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本帖最后由 shadowkill 于 2012-6-10 21:39 编辑
看了小鱼老湿讲的elseif 语句
#include <stdio.h>
void main()
{
char c;
c = getchar();
if (c<32)
{
printf("this a control char\n");
}
else if (c>= 'o'&&c <='9')
{
printf("this is a digit\n");
}
else if (c>= 'A'&&c <='Z')
{
printf("this is a capital letter\n");
}
else if (c>= 'a'&&c <='z')
{
printf("this is a small letter\n");
}
else printf("this a is a son of the bitch\n");
}
视频上是这样的,但是要输入字母,然后计算机进行判断,我就该了一下,我的想法是直接输入数字然后转换成字符进行比较
如下
#include <stdio.h>
void main()
{
char c;
printf("input a number:\n");
scanf("%d\n",&c);
printf("c=%c\n",c);
if (c<32)
{
printf("this a control char\n");
}
else if (c>= 'o'&&c <='9')
{
printf("this is a digit\n");
}
else if (c>= 'A'&&c <='Z')
{
printf("this is a capital letter\n");
}
else if (c>= 'a'&&c <='z')
{
printf("this is a small letter\n");
}
else printf("this a is a son of the bitch\n");
}
虽然成功了但是我发现要输入两次,不知道问题出在哪里了?
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