|
马上注册,结交更多好友,享用更多功能^_^
您需要 登录 才可以下载或查看,没有账号?立即注册
x
- #include <stdio.h>
- #include <stdlib.h>
- #include <string.h>
- #include <time.h>
- //**************************************************************************
- //实现一个洗牌程序。所谓洗牌程序,就是将所有的扑克牌放入一个数组中,
- //要求把数组内的扑克牌顺序随机打乱,然后输出
- //每个人获得14张牌 ,我分牌的思路是牌在数组里面随机生成0~54的不重复的54个数,规定自然数0~12为 {"方","梅","红","黑","大王","小王"}里面的方,
- //13-26w为梅有,依次类推,最后剩余的52,53两个数分别对应大小王,对i循环从1-14,依次对应纸牌里面的1-13,然后成对输出
- int number_of_game = 3;
- int card = 13;
- //int print_card(int i,char name);
- //int distribution(int array,int member);
- //char **get_name(int num);
- //***********************生成54个0~54的整数,乱序***********************************
- //确保新生成的数组里面没有
- //返回1表示这个数在数组里面已经存在了
- int compare(int array[],int number,int length)
- {
- int i;
- int sign = 0;
- // length = sizeof(array) / sizeof(array[0]); array是数组形式,但实际上是一个指针,这样无法计算数组的长度
- for(int i =0;i<length;i++)
- {
- if (array[i] == number)
- {
- sign = 1;
- break;
- }
- }
- return sign;
- }
- int *get_54_number_no_repeat(int num)
- {
- int *total_card;
- int i,number,label;
- total_card = (int *) malloc(sizeof(int) * num);
- for(int i =0;i<num;i++)
- {
- number = rand() % 54;
- if (i == 0)
- {
- total_card[i] = number;
- }
- else
- {
- label = compare(total_card,number,i);
- // printf("label = %d\n",label) ;
- if (label == 0)
- {
- //printf("label = 0,未出现重复,程序继续") ;
- total_card[i] = number;
- }
- else
- {
- //printf("label = 1,出现重复,重新获取随机数") ;
- do
- {
- number = rand() % 54;
- label = compare(total_card,number,i);
- //printf("label = %d\n",label) ;
- }while(label == 1);
- total_card[i] = number;
- }
-
- }
- }
- return total_card;
- }
- void print_card(int i , char name[] ,int people[13],char class_card[][7])
- {
- // printf("**************%d*************\n",i);
- int card = 13;
- printf("the card of %s is:\n", name);
-
- for(int i =0;i<13;i++)
- {
- printf("in the function%s \n",class_card[i]);
- // printf("in the function%d \n",people[i]);
- }
- for (int i = 0; i < card; i++)
- {
- if(people[i] < card - 1) //小于13
- {
- printf("<13 people[i] = %d\n",people[i]);
- printf("%s%d ",class_card[0],i); //0~14给第一个字符
-
- }
-
- else if(card *2 > people[i] >= card)
- {
- printf("26> >13 people[i] = %d\n",people[i]);
- printf("%s%d ",class_card[1],i);
- }
-
- else if(card *3 > people[i] >= card *2)
- {
- printf("39> >26 people[i] = %d\n",people[i]);
- printf("%s%d ",class_card[2],i);
-
- }
-
- else if(52 > people[i] >= 39)
- {
- printf("52> >39 people[i] = %d\n",people[i]);
- printf("%s%d ",class_card[3],i);
-
- }
- else if(people[i] == 53)
- {
- printf("%s ",class_card[4]);
- }
- else if(people[i] == 54)
- {
- printf("%s ",class_card[5]);
- }
- }
- }
- void get_name(char name[][64] , int num)
- {
- int i ;
- for(i = 0 ; i < number_of_game ; i ++)
- {
- printf("enter %d member's name :",i) ;
- fgets(name[i] , 64 , stdin) ;
- }
- }
- int * distribution(int *array,int member)
- {
- int * someone ;
- someone = (int *) malloc(sizeof(int) * 14) ;
- for(int i = 0 ; i < card ; i ++)
- {
- someone[i] = array[card * (member - 1) + i] ;
- }
- return someone ;
- }
- int main()
- {
- //输入玩家的名子
- int i;
- char name[3][64] ;
- get_name(name , number_of_game) ;
- // for(i = 0; i < number_of_game; i++)
- // {
- // printf("the %d member's name is: %s'",i,name[i]);
- // }
-
- //定义纸牌
- //char *num[13] = {'J','Q','K'};
- char num[13][4] = {"1","2","3","4","5","6","7","8","9","10","J","Q","K"} ;
- char class_card[][7] = {"方","梅","红","黑","大王","小王"};
-
-
- //分配54张牌
- int *person1,*person2,*person3;
- int *people;
-
- people = get_54_number_no_repeat(54);
-
- person1 = distribution(people,1);
- person2 = distribution(people,2);
- person3 = distribution(people,3);
-
- //打印3个人分到的牌
- print_card(1,name[0],person1,class_card);
- print_card(2,name[1],person2,class_card);
- print_card(3,name[2],person3,class_card);
-
- free(person1);
- free(person2);
- free(person3);
- return 0;
- }
复制代码
我这里之前回复过的一洗牌、发牌程序,供你参考一下
- #include <stdio.h>
- #include <stdlib.h>
- #include <time.h>
- void shuffle(int array[], int length);
- void deal(int array[], int player[3][14]);
- void show(char names[3][20], int player[3][14]);
- void shuffle(int array[], int length) // 调用函数 shuffle 进行洗牌
- {
- int index, temp, i;
- srand(time(NULL)); // 使用当前时间进行随机数发生器的初始化
- for (i = 0; i < length; i++)
- {
- index = rand() % (length - i + 1) + i; // 产生一个随机数
- if (index != i) // 如果 index 不等于 i,这是为了充分打乱 array 中的原值,即109行所赋的值
- {
- temp = array[i]; // 将原值(第 i 张牌)赋给临时变量
- array[i] = array[index]; // 将第 index 张牌替换原值
- array[index] = temp; // 将第 i 张牌换到第 index 张牌的位置
- }
- }
- }
- void deal(int array[], int player[3][14])
- {
- int i, j, k = 0;
- // 模拟发牌:拿起一副无序的扑克每人轮流发一张牌
- for (i = 0; i < 14; i++)
- {
- for (j = 0; j < 3; j++)
- {
- player[j][i] = array[k++];
- }
- }
- }
- void show(char names[3][20], int player[3][14])
- {
- int i, j, poker;
- printf("\n方=方角,梅=梅花,红=红桃,黑=黑桃\n\n");
- for (i = 0; i < 3; i++)
- {
- printf("%s手上的牌是:", names[i]);
- for (j = 0; j < 14; j++)
- {
- poker = player[i][j];
- if (poker < 11 && 0 < poker)
- {
- printf("方%d ", poker);
- }
- else if (poker < 21 && 10 < poker)
- {
- printf("梅%d ", poker-10);
- }
- else if (poker < 31 && 20 < poker)
- {
- printf("红%d ", poker-20);
- }
- else if (poker < 41 && 30 < poker)
- {
- printf("黑%d ", poker-30);
- }
- else
- {
- switch (poker)
- {
- case 41: printf("方J "); break;
- case 42: printf("方Q "); break;
- case 43: printf("方K "); break;
- case 44: printf("梅J "); break;
- case 45: printf("梅Q "); break;
- case 46: printf("梅K "); break;
- case 47: printf("红J "); break;
- case 48: printf("红Q "); break;
- case 49: printf("红K "); break;
- case 50: printf("黑J "); break;
- case 51: printf("黑Q "); break;
- case 52: printf("黑K "); break;
- case 53: printf("小王 "); break;
- case 54: printf("大王 "); break;
- }
- }
- }
- printf("\n\n");
- }
- }
- int main(void)
- {
- int array[54];
- int player[3][14];
- int i,ch;
- char names[3][20];
- // 初始化扑克牌
- // 1~10代表方(角)1~10, 41、42、43代表方(角)J、Q、K
- // 11~20代表梅(花)1~10, 44、45、46代表梅(花)J、Q、K
- // 21~30代表红(桃)1~10, 47、48、49代表红(桃)J、Q、K
- // 31~40代表黑(桃)1~10, 50、51、52代表黑(桃)J、Q、K
- // 53、54当然就代表小王大王啦~
- for (i = 0; i < 54; i++)
- {
- array[i] = i + 1;
- }
- for (i = 0; i < 3; i++)
- {
- printf("\n请输入%d号玩家的名字:", i+1);
- scanf("%s",names[i]);
- }
- do
- {
- shuffle(array, 54);
- deal(array, player);
- show(names, player);
- printf("重新洗牌(Y/N)?");
- do
- {
- ch = getchar(); // 过滤输入缓冲区的其他字符
- } while (ch != 'Y' && ch != 'N');
- } while (ch == 'Y');
- return 0;
- }
复制代码
|
|