找到问题了,来个自我解答吧
最后一个为字节型数据,必须+2+2移动
因此引进SIl来指向最后一种数据
新的代码如下:
- assume cs:codeseg,ds:dataseg,ss:stackseg
- stackseg segment
- dw 0,0,0,0,0,0,0,0
- stackseg ends
- dataseg segment
- db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
- db '1984','1985','1986','1987','1987','1988','1989','1990','1991'
- db '1993','1994','1995'
- dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
- dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
- dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
- dw 11542,14430,15257,17800
- dataseg ends
- table segment
- db 21 dup ('year summ ne ?? ')
- table ends
- codeseg segment
- start: mov ax,table
- mov ds,ax
- mov bx,0
- mov ax,dataseg
- mov es, ax
- mov ax,stackseg
- mov ss,ax
- mov di,0
- mov si,0
-
- mov cx,21
- s:mov ax,es:[di]
- mov [bx+0],ax
- mov ax,es:[di+2]
- mov [bx+2],ax
-
- mov ax,es:[di+84]
- mov [bx+5],ax
- mov ax,es:[di+86]
- mov [bx+7],ax
-
- mov ax,es:[si+168]
- mov [bx+10],ax
- mov ax,[bx+5]
- mov dx,[bx+7]
- div word ptr[bx+10]
- mov [bx+13],ax
-
- add si,2
- add di,4
- add bx,16
- loop s
-
-
- mov ax,4c00h
- int 21h
- codeseg ends
- end start
-
-
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