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本帖最后由 Judie 于 2021-4-6 14:31 编辑
- 26. Remove Duplicates from Sorted Array
- Given a sorted array nums, remove the duplicates in-place such that each element appears only once and returns the new length.
- Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
- Clarification:
- Confused why the returned value is an integer but your answer is an array?
- Note that the input array is passed in by reference, which means a modification to the input array will be known to the caller as well.
- Internally you can think of this:
- // nums is passed in by reference. (i.e., without making a copy)
- int len = removeDuplicates(nums);
- // any modification to nums in your function would be known by the caller.
- // using the length returned by your function, it prints the first len elements.
- for (int i = 0; i < len; i++) {
- print(nums[i]);
- }
-
- Example 1:
- Input: nums = [1,1,2]
- Output: 2, nums = [1,2]
- Explanation: Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn't matter what you leave beyond the returned length.
- Example 2:
- Input: nums = [0,0,1,1,1,2,2,3,3,4]
- Output: 5, nums = [0,1,2,3,4]
- Explanation: Your function should return length = 5, with the first five elements of nums being modified to 0, 1, 2, 3, and 4 respectively. It doesn't matter what values are set beyond the returned length.
-
- Constraints:
- 0 <= nums.length <= 3 * 104
- -104 <= nums[i] <= 104
- nums is sorted in ascending order.
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