请教，谢谢

python---1

def func(listinfo):
    try:
        result = filter(lambda k: k<100 and k%2==0, listinfo)
    except Exception as err:
        return err
    else:
        print(list(result))
        return False

listinfo = [133, 88, 33, 22, 44, 11, 44, 55, 33, 22, 11, 11, 444, 66, 555]
assert func(listinfo)

结果[88, 22, 44, 44, 22, 66]
Traceback (most recent call last):
  File "C:/Users/Administrator/AppData/Local/Programs/Python/Python38/1.py", line 11, in <module>
    assert func(listinfo)
AssertionError

wp231957

你为啥要加assert   看不懂

terry_zxf

def func(listinfo):
    try:
        result = filter(lambda k: k<100 and k%2==0, listinfo)
    except Exception as err:
        return err
    else:
        print(list(result))
       return False //我觉得问题在这里  你返回false

listinfo = [133, 88, 33, 22, 44, 11, 44, 55, 33, 22, 11, 11, 444, 66, 555]
assert func(listinfo)


try ....except...else 语句，当没有异常发生时，else中的语句将会被执行。

你理解应该反了， else 这里和except 是逻辑队列 ，try是执行队列先于逻辑队列执行，然后逻辑队列再判断二选一。

python---1

题目要求断言返回结果的类型啊

python---1

谢谢