[已解决]求住以下python 实现代码

kaohsing · 发表于 2021-7-17 07:32:42

#!/usr/bin/python
import re
s='''Hmm~ There's a hero If you look inside your heart You don't have to be afraid
Of what you are There's an answer If you reach into your soul
And the sorrow that you know Will melt away And then a hero comes along
With the strength to carry on And you cast your fears aside
And you know you can survive So when you feel like hope is gone
Look inside you and be strong And you'll finally see the truth
That a hero lies in you abcdeabcde It's a long road When you face the world alone
No one reaches out a hand or you to hold You can find love
If you search within yourself And the emptiness you felt will disappear
And then a hero comes along With the strength to carry on And you cast your fears aside
And you know you can survive So when you feel like hope is gone
Look inside you and be strong And you'll finally see the truth
That a hero lies in you Lord knows......Dreams are hard to follow
'''
def k(s):
result=""
l=list( set(re.findall(r'(\w{2,})', s)))
z=sorted(l,key=lambda l: len(l))
result=z[-1]
a=len(z.pop())
for i in z[::-1]:
if (len(i)==a):
result=result+","+i
else:
return result
print(k(s))

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kaohsing · 发表于 2021-7-17 09:41:54

#!/usr/bin/python
import re
s='''Hmm~ There's a hero If you look inside your heart You don't have to be afraid
Of what you are There's an answer If you reach into your soul
And the sorrow that you know Will melt away And then a hero comes along
With the strength to carry on And you cast your fears aside
And you know you can survive So when you feel like hope is gone
Look inside you and be strong And you'll finally see the truth
That a hero lies in you abcdeabcde It's a long road When you face the world alone
No one reaches out a hand or you to hold You can find love
If you search within yourself And the emptiness you felt will disappear
And then a hero comes along With the strength to carry on And you cast your fears aside
And you know you can survive So when you feel like hope is gone
Look inside you and be strong And you'll finally see the truth
That a hero lies in you Lord knows......Dreams are hard to follow abcdeabcde
'''
def k(m):
global i
z=len(m[0])
if(z>=i):
if(z>i):
l.clear()
i=z
l.append(m[0])
def kao(s):
re.sub('(\w+)', k, s)
return l
i=1
l=[]
print(kao(s))

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Twilight6 · 发表于 2021-7-17 11:43:05

青出于蓝发表于 2021-7-15 22:07
遇到问题要多思考
上边代码最重要的是split函数，将字符串分割

这个字符：'I Love FishC! I Love Python! I Love Window!'

自己测试下代码，字符都没去掉

没过 7 天别那么着急的举报得最佳，是你的最佳都会是你的哈

青出于蓝 · 发表于 2021-7-17 11:54:06

Twilight6 发表于 2021-7-17 11:43
这个字符：'I Love FishC! I Love Python! I Love Window!'

自己测试下代码，字符都没去掉

哦吼
原来是这样.................................................

weiyideid823 · 发表于 2021-7-17 17:46:44

聂嘉辉发表于 2021-7-16 22:39
最讨厌这种不劳而获的。你一个代码不写，有些人太善良了，你遇到问题请教一下没什么，但是什么都没有就很可 ...

我也讨厌这种人啊，但是由于各种原因我就成了这种人，你要是喷了之后还有时间的话可以看看我早期的帖子都是有自己的想法的，不过没时间也无所谓啦

0HB · 发表于 2021-7-18 02:45:44

本帖最后由 0HB 于 2021-7-19 01:10 编辑

复制代码

（后补充：不好意思，看错需求了，以为是出现最多次的单词.... ）

0HB · 发表于 2021-7-18 02:50:14

本帖最后由 0HB 于 2021-7-18 03:00 编辑

0HB 发表于 2021-7-18 02:45
Sr = input('请输入句子：')
list1 = Sr.split()
list2 = [0]

希望有帮助。用的知识都很基础

（后补充：不好意思，看错需求了，以为是出现最多次的单词....

）

0HB · 发表于 2021-7-18 03:09:02

本帖最后由 0HB 于 2021-7-19 01:11 编辑

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