请用一行代码找出“败家仔”

wwk_0726 · 发表于 2023-11-7 10:04:38

11111111111

yiyundi · 发表于 2023-11-7 14:35:38

13鱼素 · 发表于 2023-11-7 21:59:05

看看

TingfYu · 发表于 2023-11-11 16:35:21

丢的FC · 发表于 2023-12-16 01:08:25

苗生海海 · 发表于 2023-12-16 13:27:50

x = [key for key, value in screen_times.items() if value['购物'] > 60]

mengtaiqi · 发表于 2023-12-16 18:00:17

misajdisajdio · 发表于 2023-12-25 10:41:14

x = [k for k,v in screen_times.items() if v['购物'] > 60]

zhangchenyvn · 发表于 2024-2-19 12:46:33

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life我知你心 · 发表于 2024-2-20 14:39:16

x = [name for name, times in screen_times.items() if times.get('购物', 0) > 60]

NanShan_bob · 发表于 2024-5-25 14:23:01

x = [i for i in screen_times if list(screen_times[i].values())[3] > 60 ]

zxbin1 · 发表于 2024-5-25 21:09:25

我只能这样了

x = [[a for s in screen_times[a] if s=="购物" and screen_times[a][s]>60] for a in screen_times]

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15135710508 · 发表于 2024-10-24 08:30:51

x = [name for name in screen_times if screen_times[name]["购物"]>60]

猪猪女孩_Lei · 发表于 2024-11-12 16:08:21

ahnseil · 发表于 2024-11-29 17:38:31

x = [(name,screen_times[name]["购物"]) for name in screen_times if screen_times[name]["购物"] > 60]

jjkang · 发表于 2024-12-7 17:24:50

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岳军任 · 发表于 2024-12-17 11:36:46

grad_div · 发表于 2024-12-17 15:42:29

x = [_ for _ in screen_times if screen_times[_]["购物"] > 60]

player-none · 发表于 2025-4-27 22:58:34

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[一行流] 请用一行代码找出“败家仔”