请用一行代码找出不及格的奥特曼

嘉岳呀

奥特曼考试不及格？

Brrrc

z = [name for name in ultraman if min(ultraman[name].values()) < 60]

冬雪雪冬

1. z = [i for i, j in ultraman.items() if min(j.values()) < 60]

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painx

z=[k if v2 < 60for k,v in ultraman for k2,v2 in v ]

982304048

.

小甲鱼的二师兄

想不出来！！

Coding_forever

1

蓝雨泽

1

蓝雨泽

回复

sryml

1. z = {min(val.values()) < 60 and key for key, val in ultraman.items()} - {False}

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过默

xc

魔界风信子

学习

python爱好者.

1. ultraman = {
   
2.         "迪迦" : {"语文":83, "数学":99, "英语":36},
   
3.         "艾斯" : {"语文":85, "数学":39, "英语":82},
   
4.         "泰罗" : {"语文":99, "数学":84, "英语":78},
   
5.         "佐菲" : {"语文":59, "数学":54, "英语":98},
   
6.         "赛文" : {"语文":95, "数学":93, "英语":94}}
   
7. 
   
8. z = [i[0] for i in ultraman.items() if min(i[1].values()) < 60]
   
9. 
   
10. print(z)
    

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在东边

1. z = [k for k, v in ultraman.items() if any(x < 60 for x in v.values())]

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alee2022

.

6boy

z= [each for each  in ultraman.keys() for i in ('语文','数学','英语') if ultraman[each][i]  < 60]

eeffve

离开家长

xiannv2b

1

hanhm85

z = [set(k for k,v in ultraman.items() for k1,v1 in v.items() if v1<60)]