请用一行代码找出猪队友

522victor

看看啊

arkia123

z

刘jcccccc

1

敞天Py

1

cuijiyuan

查看答案

shaoxuan1024

atoms

学习学习！

FoolZenYin_甫寸

x = [':'.join((i, min(members[i].items(), key = lambda x:x[1])[0])) for i in members]

junmishow

1

鑫xx

x = [':'.join((i, min(members[i].items(), key = lambda x:x[1])[0]))
     for i in members]

Rachel01

x = [':'.join([v[0], list(filter(lambda k: k[1] is min(list(v[1].values())), v[1].items()))[0][0]]) for v in members.items()]

七刀会

来看解析

painx

双重循环。

从零开始的修炼

111111111111

Snxsky

1

suyas9445

[f"{k}:{min(members[k].items(), key=lambda x : x[1])[0]}" for k in members]

蕾米莉亚1122

eat蟒蛇

回复可见猪队友

panwei0774

看看

SQ551

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