[已解决]谁能解释下X这串代码 小甲鱼找猪队友那题

Angelina_Jolie

members = {
    "鱼C工作室" : {"小甲鱼":83, "不二如是":89, "二师兄":64, "小师妹":75, "鱼小二":96},
    "复仇者联盟" : {"钢铁侠":85, "绿巨人":39, "黑寡妇":82, "鹰眼":73, "雷神":99},
    "奥特曼家族" : {"迪迦":99, "艾斯":84, "泰罗":63, "佐菲":78, "赛文":78}}

x = [o+":"+min(members[o], key=members[o].get) for o in members]

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最佳答案

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ouyunfu

2021-11-8 10:41:13

members = {
    "鱼C工作室" : {"小甲鱼":83, "不二如是":89, "二师兄":64, "小师妹":75, "鱼小二":96},
    "复仇者联盟" : {"钢铁侠":85, "绿巨人":39, "黑寡妇":82, "鹰眼":73, "雷神":99},
    "奥特曼家族" : {"迪迦":99, "艾斯":84, "泰罗":63, "佐菲":78, "赛文":78}}

x = [o+":"+min(members[o], key=members[o].get) for o in members]
# [i for i in j] 通过for循环创建一个数组
# a+b+c 这是简单的字符串合并
# min(a, key=b)找到a中b值最小的
# members[o].get 获取字典的value
# 所以min(members[o], key=members[o].get)就是将字典的value进行排序，并返回value最小的key
# 比如"鱼C工作室" 中“二师兄”的value最小，“二师兄”作为字典的key被返回

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ouyunfu

members = {
    "鱼C工作室" : {"小甲鱼":83, "不二如是":89, "二师兄":64, "小师妹":75, "鱼小二":96},
    "复仇者联盟" : {"钢铁侠":85, "绿巨人":39, "黑寡妇":82, "鹰眼":73, "雷神":99},
    "奥特曼家族" : {"迪迦":99, "艾斯":84, "泰罗":63, "佐菲":78, "赛文":78}}

x = [o+":"+min(members[o], key=members[o].get) for o in members]
# [i for i in j] 通过for循环创建一个数组
# a+b+c 这是简单的字符串合并
# min(a, key=b)找到a中b值最小的
# members[o].get 获取字典的value
# 所以min(members[o], key=members[o].get)就是将字典的value进行排序，并返回value最小的key
# 比如"鱼C工作室" 中“二师兄”的value最小，“二师兄”作为字典的key被返回