[已解决]举一反三不会

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怎么用for代替while输出完全相同的内容（包括格式）

1. ten_things = "Apples Oranges Crows Telephone Light Sugar"
   
2. 
   
3. print("Wait there are not 10 things in that list.Let's fix that.")
   
4. 
   
5. stuff = ten_things.split(' ')
   
6. more_stuff = ["Day", "Night", "Song", "Frisbee",
   
7.                 "Corn", "Banana", "Gril", "Boy"]
   
8. 
   
9. 
   
10. while len(stuff) != 10:
    
11.     next_one = more_stuff.pop()
    
12.     print("Adding:", next_one)
    
13.     stuff.append(next_one)
    
14.     print(f"There are {len(stuff)} items now.")
    
15. 
    
16. print("There we go: ", stuff)
    
17. 
    
18. print("Let's do some things with stuff.")
    
19. 
    
20. print(stuff[1])
    
21. print(stuff[-5])# whoa! fancy
    
22. print(stuff.pop())
    
23. print(' '.join(stuff)) # what? cool!
    
24. print('#'.join(stuff[3:5])) # super stellar!
    

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最佳答案

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jackz007

2021-11-14 12:56:46

1. ten_things = "Apples Oranges Crows Telephone Light Sugar"
   
2. 
   
3. print("Wait there are not 10 things in that list.Let's fix that.")
   
4. 
   
5. stuff = ten_things.split(' ')
   
6. more_stuff = ["Day", "Night", "Song", "Frisbee",
   
7.                 "Corn", "Banana", "Gril", "Boy"]
   
8. 
   
9. n = 10 - len(stuff)
   
10. for _ in range(n):
    
11.     next_one = more_stuff.pop()
    
12.     print("Adding:", next_one)
    
13.     stuff.append(next_one)
    
14.     print(f"There are {len(stuff)} items now.")
    
15. 
    
16. print("There we go: ", stuff)
    
17. 
    
18. print("Let's do some things with stuff.")
    
19. 
    
20. print(stuff[1])
    
21. print(stuff[-5])# whoa! fancy
    
22. print(stuff.pop())
    
23. print(' '.join(stuff)) # what? cool!
    
24. print('#'.join(stuff[3:5])) # super stellar!

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        运行实况：

1. D:\00.Excise\Python>python x.py
   
2. Wait there are not 10 things in that list.Let's fix that.
   
3. Adding: Boy
   
4. There are 7 items now.
   
5. Adding: Gril
   
6. There are 8 items now.
   
7. Adding: Banana
   
8. There are 9 items now.
   
9. Adding: Corn
   
10. There are 10 items now.
    
11. There we go:  ['Apples', 'Oranges', 'Crows', 'Telephone', 'Light', 'Sugar', 'Boy
    
12. ', 'Gril', 'Banana', 'Corn']
    
13. Let's do some things with stuff.
    
14. Oranges
    
15. Sugar
    
16. Corn
    
17. Apples Oranges Crows Telephone Light Sugar Boy Gril Banana
    
18. Telephone#Light
    
19. 
    
20. D:\00.Excise\Python>

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跳转到最佳答案楼层

jackz007

1. ten_things = "Apples Oranges Crows Telephone Light Sugar"
   
2. 
   
3. print("Wait there are not 10 things in that list.Let's fix that.")
   
4. 
   
5. stuff = ten_things.split(' ')
   
6. more_stuff = ["Day", "Night", "Song", "Frisbee",
   
7.                 "Corn", "Banana", "Gril", "Boy"]
   
8. 
   
9. n = 10 - len(stuff)
   
10. for _ in range(n):
    
11.     next_one = more_stuff.pop()
    
12.     print("Adding:", next_one)
    
13.     stuff.append(next_one)
    
14.     print(f"There are {len(stuff)} items now.")
    
15. 
    
16. print("There we go: ", stuff)
    
17. 
    
18. print("Let's do some things with stuff.")
    
19. 
    
20. print(stuff[1])
    
21. print(stuff[-5])# whoa! fancy
    
22. print(stuff.pop())
    
23. print(' '.join(stuff)) # what? cool!
    
24. print('#'.join(stuff[3:5])) # super stellar!

复制代码

        运行实况：

1. D:\00.Excise\Python>python x.py
   
2. Wait there are not 10 things in that list.Let's fix that.
   
3. Adding: Boy
   
4. There are 7 items now.
   
5. Adding: Gril
   
6. There are 8 items now.
   
7. Adding: Banana
   
8. There are 9 items now.
   
9. Adding: Corn
   
10. There are 10 items now.
    
11. There we go:  ['Apples', 'Oranges', 'Crows', 'Telephone', 'Light', 'Sugar', 'Boy
    
12. ', 'Gril', 'Banana', 'Corn']
    
13. Let's do some things with stuff.
    
14. Oranges
    
15. Sugar
    
16. Corn
    
17. Apples Oranges Crows Telephone Light Sugar Boy Gril Banana
    
18. Telephone#Light
    
19. 
    
20. D:\00.Excise\Python>

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