[已解决]用matplotlib绘制的条形图，条形重合

Jay8

1. import pandas as pd
   
2. import matplotlib.pyplot as plt
   
3. 
   
4. 
   
5. phones = pd.read_excel('D:\测试.xlsx',)
   
6. 
   
7. 
   
8. plt.rcParams ['font.sans-serif'] = ['SimHei']
   
9. plt.rcParams ['axes.unicode_minus'] = False
   
10. 
    
11. 
    
12. x = phones['品牌']
    
13. y = phones['淘宝销量']
    
14. z = phones['京东销量']
    
15. 
    
16. 
    
17. plt.bar(x,y,color='g',label="淘宝销量",alpha=0.5,width=0.4)
    
18. plt.bar(x,z,color='b',label='京东销量',width=0.4)
    
19. 
    
20. plt.legend()
    
21. plt.show()

复制代码

excel表就是以下这些内容
品牌        淘宝销量        京东销量
小米            9                   8
荣耀           20                   30
华为            5                   4


代码运行后出现的图表两条柱状是重合的，
直接在x后加数字会报错TypeError: can only concatenate str (not "float") to str
请问应该用什么方法才能将两个条形分开，
求解答

最佳答案

月排行榜 / 总排行榜

suchocolate

2021-12-10 16:07:11

直接抄官网

1. import matplotlib.pyplot as plt
   
2. 
   
3. plt.rcParams['font.sans-serif'] = ['SimHei']
   
4. plt.rcParams['axes.unicode_minus'] = False
   
5. 
   
6. labels = ['小米', '荣耀', '华为']
   
7. taobao = [9, 20, 5]
   
8. jingdong = [8, 30, 4]
   
9. x = [1, 2, 3]
   
10. width = 0.35  # the width of the bars
    
11. 
    
12. fig, ax = plt.subplots()
    
13. rects1 = ax.bar([i - width / 2 for i in x], taobao, width, label='淘宝')
    
14. rects2 = ax.bar([i + width / 2 for i in x], jingdong, width, label='京东')
    
15. 
    
16. # Add some text for labels, title and custom x-axis tick labels, etc.
    
17. ax.set_ylabel('销量')
    
18. ax.set_title('销量对比')
    
19. ax.set_xticks(x)
    
20. ax.set_xticklabels(labels)
    
21. ax.legend()
    
22. 
    
23. 
    
24. def autolabel(rects):
    
25.     """Attach a text label above each bar in *rects*, displaying its height."""
    
26.     for rect in rects:
    
27.         height = rect.get_height()
    
28.         ax.annotate('{}'.format(height),
    
29.                     xy=(rect.get_x() + rect.get_width() / 2, height),
    
30.                     xytext=(0, 3),  # 3 points vertical offset
    
31.                     textcoords="offset points",
    
32.                     ha='center', va='bottom')
    
33. 
    
34. 
    
35. autolabel(rects1)
    
36. autolabel(rects2)
    
37. 
    
38. fig.tight_layout()
    
39. 
    
40. plt.show()
    

复制代码

跳转到最佳答案楼层

suchocolate

直接抄官网

1. import matplotlib.pyplot as plt
   
2. 
   
3. plt.rcParams['font.sans-serif'] = ['SimHei']
   
4. plt.rcParams['axes.unicode_minus'] = False
   
5. 
   
6. labels = ['小米', '荣耀', '华为']
   
7. taobao = [9, 20, 5]
   
8. jingdong = [8, 30, 4]
   
9. x = [1, 2, 3]
   
10. width = 0.35  # the width of the bars
    
11. 
    
12. fig, ax = plt.subplots()
    
13. rects1 = ax.bar([i - width / 2 for i in x], taobao, width, label='淘宝')
    
14. rects2 = ax.bar([i + width / 2 for i in x], jingdong, width, label='京东')
    
15. 
    
16. # Add some text for labels, title and custom x-axis tick labels, etc.
    
17. ax.set_ylabel('销量')
    
18. ax.set_title('销量对比')
    
19. ax.set_xticks(x)
    
20. ax.set_xticklabels(labels)
    
21. ax.legend()
    
22. 
    
23. 
    
24. def autolabel(rects):
    
25.     """Attach a text label above each bar in *rects*, displaying its height."""
    
26.     for rect in rects:
    
27.         height = rect.get_height()
    
28.         ax.annotate('{}'.format(height),
    
29.                     xy=(rect.get_x() + rect.get_width() / 2, height),
    
30.                     xytext=(0, 3),  # 3 points vertical offset
    
31.                     textcoords="offset points",
    
32.                     ha='center', va='bottom')
    
33. 
    
34. 
    
35. autolabel(rects1)
    
36. autolabel(rects2)
    
37. 
    
38. fig.tight_layout()
    
39. 
    
40. plt.show()
    

复制代码

Jay8

suchocolate 发表于 2021-12-10 16:07
直接抄官网

感谢回答