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在做第一个循环的时候遇到了编译问题,没有看出来问题在哪儿,解决了一个又出现一个,不知道怎么办了,麻烦各位帮忙看看!
问题提示是:<40> :error A2070:invalid instruction operands!
assume cs:codesg,ss:stack,es:table,ds:data
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
stack segment
dw 0,0,0,0,0,0,0,0
stack ends
codesg segment
start:mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov ax,stack
mov ss,ax
mov sp,16
mov si,0
mov di,0
mov bx,0
mov cx,3
s:push cx
mov cx,8
s0:mov es:[di],ds:[bx+si]
inc si
add di,16
loop s0
pop cx
add bx,36
loop s
mov ax,4c00h
int 21h
codesg ends
end start
本帖最后由 jackz007 于 2021-12-14 15:26 编辑
这条指令是无效的
- s0:mov es:[di],ds:[bx+si]
复制代码
mov 指令不允许两个操作数都是内存地址
这是我修改的代码,你可以关注一下堆栈段的定义和初始化相关的代码。
- assume cs:code , es:table , ds:data
- data segment para public 'DATA'
- db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
- db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
- db '1993','1994','1995'
- dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
- dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
-
- dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
- dw 11542,14430,15257,17800
- data ends
- table segment para public 'TABLE'
- db 21 dup ('year summ ne ?? ')
- table ends
- stack segment para stack 'STACK'
- dw 200h dup(0)
- stack ends
- code segment para public 'CODE'
- main proc far
- mov ax,data
- mov ds,ax
- mov ax,table
- mov es,ax
- xor bx,bx
- xor dx,dx
- xor si,si
- mov cx,21
- cld
- s:push si
- movsw
- movsw
- add si,80
- inc di
- movsw
- movsw
- add si,80
- add si,dx
- sub si,bx
- inc di
- movsw
- pop si
- add si,4
- add di,4
- add bx,4
- add dx,2
- loop s
- mov ax,4c00h
- int 21h
- main endp
- code ends
- end main
复制代码
运行实况:
- -d es:0 l150
- 14B3:0000 31 39 37 35 20 10 00 00-00 20 03 00 20 3F 3F 20 1975 .... .. ??
- 14B3:0010 31 39 37 36 20 16 00 00-00 20 07 00 20 3F 3F 20 1976 .... .. ??
- 14B3:0020 31 39 37 37 20 7E 01 00-00 20 09 00 20 3F 3F 20 1977 ~... .. ??
- 14B3:0030 31 39 37 38 20 4C 05 00-00 20 0D 00 20 3F 3F 20 1978 L... .. ??
- 14B3:0040 31 39 37 39 20 56 09 00-00 20 1C 00 20 3F 3F 20 1979 V... .. ??
- 14B3:0050 31 39 38 30 20 40 1F 00-00 20 26 00 20 3F 3F 20 1980 @... &. ??
- 14B3:0060 31 39 38 31 20 80 3E 00-00 20 82 00 20 3F 3F 20 1981 .>.. .. ??
- 14B3:0070 31 39 38 32 20 A6 5F 00-00 20 DC 00 20 3F 3F 20 1982 ._.. .. ??
- 14B3:0080 31 39 38 33 20 91 C3 00-00 20 DC 01 20 3F 3F 20 1983 .... .. ??
- 14B3:0090 31 39 38 34 20 C7 7C 01-00 20 0A 03 20 3F 3F 20 1984 .|.. .. ??
- 14B3:00A0 31 39 38 35 20 81 24 02-00 20 E9 03 20 3F 3F 20 1985 .$.. .. ??
- 14B3:00B0 31 39 38 36 20 8A 03 03-00 20 A2 05 20 3F 3F 20 1986 .... .. ??
- 14B3:00C0 31 39 38 37 20 7C 47 05-00 20 D2 08 20 3F 3F 20 1987 |G.. .. ??
- 14B3:00D0 31 39 38 38 20 EB 03 09-00 20 E9 0A 20 3F 3F 20 1988 .... .. ??
- 14B3:00E0 31 39 38 39 20 CA 42 0C-00 20 C5 0F 20 3F 3F 20 1989 .B.. .. ??
- 14B3:00F0 31 39 39 30 20 18 0D 12-00 20 03 16 20 3F 3F 20 1990 .... .. ??
- 14B3:0100 31 39 39 31 20 38 1F 1C-00 20 22 20 20 3F 3F 20 1991 8... " ??
- 14B3:0110 31 39 39 32 20 58 19 2A-00 20 16 2D 20 3F 3F 20 1992 X.*. .- ??
- 14B3:0120 31 39 39 33 20 28 44 39-00 20 5E 38 20 3F 3F 20 1993 (D9. ^8 ??
- 14B3:0130 31 39 39 34 20 28 F0 46-00 20 99 3B 20 3F 3F 20 1994 (.F. .; ??
- 14B3:0140 31 39 39 35 20 68 97 5A-00 20 88 45 20 3F 3F 20 1995 h.Z. .E ??
复制代码
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