[已解决]如何用三元运算符简化这段代码

清少呐

if box == 0:
       box_x,box_y,box_z = self.box1[0],self.box1[1],self.box1[2]
 if box == 1:
            box_x,box_y,box_z = self.box2[0],self.box2[1],self.box2[2]
        if box == 2:
            box_x,box_y,box_z = self.box3[0],self.box3[1],self.box3[2]

最佳答案

月排行榜 / 总排行榜

kogawananari

2022-1-9 18:19:03

box_x,box_y,box_z,*res = getattr(self, f'box{box+1}')

跳转到最佳答案楼层

kogawananari

box_x,box_y,box_z,*res = getattr(self, f'box{box+1}')

清少呐

if box == 0:
        box_x,box_y,box_z = self.box1[0],self.box1[1],self.box1[2]
if box == 1:
        box_x,box_y,box_z = self.box2[0],self.box2[1],self.box2[2]
if box == 2:
        box_x,box_y,box_z = self.box3[0],self.box3[1],self.box3[2]

清少呐

清少呐 发表于 2022-1-9 18:19
if box == 0:
        box_x,box_y,box_z = self.box1[0],self.box1[1],self.box1[2]
if box == 1:

上面的没弄好，这个是代码

傻眼貓咪

1. box_x, box_y, box_z = self.box1[0], self.box1[1], self.box1[2] if not box else self.box2[0], self.box2[1], self.box2[2] if box < 2 else self.box3[0], self.box3[1], self.box3[2]

复制代码

傻眼貓咪

1. a = int(input("输入一个整数："))
   
2. b = "a 大于零" if a > 0 else "a 小于零" if a < 0 else "a 等于零"
   
3. print(b)

复制代码

清少呐

kogawananari 发表于 2022-1-9 23:35
box_x,box_y,box_z,*res = getattr(self, f'box{box+1}')

self.box1[0], self.box1[1], self.box1[2] 这个值如何赋值给box_x,box_y,box_z 呢

kogawananari

清少呐 发表于 2022-1-10 10:45
self.box1[0], self.box1[1], self.box1[2] 这个值如何赋值给box_x,box_y,box_z 呢

這不是已經賦值了嘛

類似於
a, b, *res = [1,2,3,4,5]