|
马上注册,结交更多好友,享用更多功能^_^
您需要 登录 才可以下载或查看,没有账号?立即注册
x
带头指针的单链表,结点插入函数传入(struct Node *head)与(struct Node **head)是否能等价操作?
函数内部关于head的部分已做对应修改
传入struct Node *head(链表始终无法增长)
- void insertNode(struct Node *head, int value){
- struct Node *previous;
- struct Node *current;
- struct Node *new;
- current = head;
- previous = NULL;
- while(current != NULL && current->value < value){
- previous = current;
- current = current->next;
- }
- new = (struct Node *)malloc(sizeof(struct Node));
- if(new == NULL){
- printf("内存分配失败!\n");
- exit(1);
- }
- new->value = value;
- new->next = current;
- if(previous == NULL){
- head = new;
- }
- else{
- previous->next = new;
- }
- }
复制代码
传入struct Node **head(能正确插入)
- void insertNode(struct Node **head, int value){
- struct Node *previous;
- struct Node *current;
- struct Node *new;
- current = *head;
- previous = NULL;
- while(current != NULL && current->value < value){
- previous = current;
- current = current->next;
- }
- new = (struct Node *)malloc(sizeof(struct Node));
- if(new == NULL){
- printf("内存分配失败!\n");
- exit(1);
- }
- new->value = value;
- new->next = current;
- if(previous == NULL){
- *head = new;
- }
- else{
- previous->next = new;
- }
- }
复制代码
本帖最后由 jackz007 于 2022-4-28 20:59 编辑
一般传指针是为了修改指针所指向内存变量的值,现在,你需要修改的是指针本身的值,那你是不是应该把指向这个指针的地址作为参数传入函数,这可不就是指向指针的指针?
|
|