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- unsigned char S_box[]={0x7,0x4,0x9,0xc,0xb,0xa,0xd,0x8,0xf,0xe,0x1,0x6,0x0,0x3,0x2,0x5};
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有这样一个数组,求解如何将该数组中的值全部取出来连接成为一个然后转换成二进制串?急
这样? - #include <stdio.h>
- void toBinary(int num, char* bin) {
- int n = 0;
- while (num) {
- bin[n++] = num % 2 ? 1 + '0' : 0 + '0';
- num /= 2;
- }
- char c;
- for (int i = 0; i < (n >> 1); ++i) {
- c = bin[i];
- bin[i] = bin[n - i - 1];
- bin[n - i - 1] = c;
- }
- bin[n] = '\0';
- }
- int main(void) {
- unsigned char S_box[] = { 0x7, 0x4, 0x9, 0xc, 0xb, 0xa, 0xd, 0x8, 0xf, 0xe, 0x1, 0x6, 0x0, 0x3, 0x2, 0x5 };
- int N = sizeof(S_box) / sizeof(unsigned char);
- char binary[N][32];
- for (int i = 0; i < N; ++i) {
- toBinary(S_box[i], binary[i]);
- }
- for (int i = 0; i < N; ++i) {
- printf("%s", binary[i]);
- }
- return 0;
- }
复制代码- 1111001001110010111010110110001111111011101110101
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