Strings

dlin1606

各位大侠，

请帮忙看一下附件上的这段代码，为什么总是出现TypeError: steps() missing 1 required positional argument: 'number'
这问题出在哪里？

多谢！

David


#Write a function called "steps" that should return a string
#that, if printed, looks like this:
#
#111
#        222
#                333
#Note that the characters at the beginning of the second and
#third lines must be tabs, not spaces. There should be one
#tab on the second line and two on the third line.
#
#You may only declare ONE string in your function.
#
#Hint: Don't overthink this! We're literally just asking you
#to return one single string that just holds the above text.
#You don't have to build the string dynamically or anything.

#Write your function here!
def steps(number):
    tabs =0
    nums=1
    for i in range(1,number+1):
         string = tabs*"\t"+str(nums)*3+'\n'
         tabs+=1
         nums+=1
         print(string)
    return ''
#The line below will test your function.
print(steps(3))

print(steps(3))
111

        222

                333

[Executed at: Sun Nov 6 17:36:12 PST 2022]

We found a few things wrong with your code. The first one is shown below, and the rest can be found in full_results.txt in the dropdown in the top left:

We expected steps to return the str
"111
        222
                333". However, it instead encountered the following error:

TypeError: steps() missing 1 required positional argument: 'number'

tommyyu

第28行直接调用了 step，没有加任何的参数，然而 step 有一个参数，第28行没有传参

dlin1606

tommyyu 发表于 2022-11-7 09:52
第28行直接调用了 step，没有加任何的参数，然而 step 有一个参数，第28行没有传参

Hello Tommy,

谢谢回复！
但是，我把28行的steps()改成steps(3)或者steps(6)，还是出现这个TypeError。
还是不知道怎么搞定这个Bug。

David

dragov

1. def steps(number):
   
2.     tabs =0
   
3.     nums=1
   
4.     for i in range(1,number+1):
   
5.          string = tabs*"\t"+str(nums)*3+'\n'
   
6.          tabs+=1
   
7.          nums+=1
   
8.          print(string)
   
9.     return ''
   
10. number=int(input("请输入数字："))
    
11. steps(number)

复制代码

tommyyu

dlin1606 发表于 2022-11-7 10:35
Hello Tommy,

谢谢回复！

我这里改完就没有问题了

dragov

最后一句的 print （ steps ( 6 ) ） 改为 steps ( 6 )

dlin1606

dragov 发表于 2022-11-7 10:47
最后一句的 print （ steps ( 6 ) ） 改为 steps ( 6 )

没有用，这个好像要在函数里面做什么改变。

jackz007

#Write a function called "steps" that should return a string
#that, if printed, looks like this:
#
#111
#        222
#                333
#Note that the characters at the beginning of the second and
#third lines must be tabs, not spaces. There should be one
#tab on the second line and two on the third line.

        别人要求 steps() 返回的是这个字符串而不是 ''

1. def steps(number):        # 函数定义要求调用的时候必须要有一个参数
   
2.     r = ''
   
3.     for i in range(number) :      
   
4.         r += '\t' * i + str(i + 1) * 3 + '\n'
   
5.     return r
   
6. print(steps(3))           # 在调用的时候，必须要提供一个参数

复制代码

dlin1606

tommyyu 发表于 2022-11-7 10:41
我这里改完就没有问题了

在我这个系统里面，这个print(steps()）里面不管输入什么数字，还是会出现这个错误，就是说系统已经假设steps()就是这样的，所有应该要在上面函数内做什么改变。

tommyyu

dlin1606 发表于 2022-11-7 10:56
在我这个系统里面，这个print(steps()）里面不管输入什么数字，还是会出现这个错误，就是说系统已经假设s ...

1. #Write a function called "steps" that should return a string
   
2. #that, if printed, looks like this:
   
3. #
   
4. #111
   
5. #        222
   
6. #                333
   
7. #Note that the characters at the beginning of the second and
   
8. #third lines must be tabs, not spaces. There should be one
   
9. #tab on the second line and two on the third line.
   
10. #
    
11. #You may only declare ONE string in your function.
    
12. #
    
13. #Hint: Don't overthink this! We're literally just asking you
    
14. #to return one single string that just holds the above text.
    
15. #You don't have to build the string dynamically or anything.
    
16. 
    
17. #Write your function here!
    
18. def steps():
    
19.     tabs =0
    
20.     number = 3
    
21.     nums=1
    
22.     for i in range(1,number+1):
    
23.          string = tabs*"\t"+str(nums)*3+'\n'
    
24.          tabs+=1
    
25.          nums+=1
    
26.          print(string)
    
27.     return ''
    
28. #The line below will test your function.
    
29. print(steps())
    

复制代码

tommyyu

dlin1606 发表于 2022-11-7 10:56
在我这个系统里面，这个print(steps()）里面不管输入什么数字，还是会出现这个错误，就是说系统已经假设s ...

或者这个行不行

1. #Write a function called "steps" that should return a string
   
2. #that, if printed, looks like this:
   
3. #
   
4. #111
   
5. #        222
   
6. #                333
   
7. #Note that the characters at the beginning of the second and
   
8. #third lines must be tabs, not spaces. There should be one
   
9. #tab on the second line and two on the third line.
   
10. #
    
11. #You may only declare ONE string in your function.
    
12. #
    
13. #Hint: Don't overthink this! We're literally just asking you
    
14. #to return one single string that just holds the above text.
    
15. #You don't have to build the string dynamically or anything.
    
16. 
    
17. #Write your function here!
    
18. def steps(nums):
    
19.     return '111\n\t222\n\t\t333'
    
20. #The line below will test your function.
    
21. print(steps(3))
    

复制代码

jackz007

tommyyu 发表于 2022-11-7 11:01

        请注意这个要求

#The line below will test your function.
print(steps(3))

print(steps(3))
111

        222

                333

tommyyu

jackz007 发表于 2022-11-7 10:54
别人要求 steps() 返回的是这个字符串而不是 ''

它的意思是不是只要返回'111\n\t222\n\t\t333'这个字符串就行了？

jackz007

tommyyu 发表于 2022-11-7 11:08
它的意思是不是只要返回'111\n\t222\n\t\t333'这个字符串就行了？

          再翻译一下这个呢：

#Write a function called "steps" that should return a string
#that, if printed, looks like this:
#
#111
#        222
#                333

tommyyu

jackz007 发表于 2022-11-7 11:12
再翻译一下这个呢：

jackz007

tommyyu 发表于 2022-11-7 11:13

        别人要求 steps() 只要返回字符串就好，无需在函数内打印，打印是别人的测试代码要做的事情。

tommyyu

那就应该这样写

1. #Write a function called "steps" that should return a string
   
2. #that, if printed, looks like this:
   
3. #
   
4. #111
   
5. #        222
   
6. #                333
   
7. #Note that the characters at the beginning of the second and
   
8. #third lines must be tabs, not spaces. There should be one
   
9. #tab on the second line and two on the third line.
   
10. #
    
11. #You may only declare ONE string in your function.
    
12. #
    
13. #Hint: Don't overthink this! We're literally just asking you
    
14. #to return one single string that just holds the above text.
    
15. #You don't have to build the string dynamically or anything.
    
16. 
    
17. #Write your function here!
    
18. def steps():
    
19.     tabs =0
    
20.     number = 3
    
21.     nums=1
    
22.     answer = ''
    
23.     for i in range(1,number+1):
    
24.          string = tabs*"\t"+str(nums)*3+'\n'
    
25.          tabs+=1
    
26.          nums+=1
    
27.          answer += (string)
    
28.     return answer
    
29. #The line below will test your function.
    
30. print(steps())
    

复制代码

jackz007

          就本题而言，感觉写 Python 代码的能力强并不重要，英语水平高似乎更为关键。

dlin1606

jackz007 发表于 2022-11-7 11:12
再翻译一下这个呢：

def steps():
    return '111\n\t222\n\t\t333'
#The line below will test your function.
print(steps())

这个就可以了。

dlin1606

tommyyu 发表于 2022-11-7 11:21
那就应该这样写

def steps():
    return '111\n\t222\n\t\t333'
#The line below will test your function.
print(steps())