[已解决]判断两个类相等

kking1

class student(object):
    def __init__(self,name,age,sex):
        self.name = name
        self.age = age
        self.sex = sex
    def __eq__(self, *args, **kwargs):
        return object.__eq__(self, *args, **kwargs)

like = student("like",25,"male")
xue = student("xue",23,"female")
dong = student("like",25,"male")

print(like is xue) #False
print(like is dong) #False
print(like == dong) #False

为啥最后一个print也是false呢？

最佳答案

月排行榜 / 总排行榜

isdkz

2023-2-20 10:47:47

因为对象的魔法方法 __eq__ 的默认行为也是判断两个对象的地址是否相等，所以 == 和 is 得到的是一样的结果，

如果你要根据属性来判断的话改成这样：

class student(object):
    def __init__(self,name,age,sex):
        self.name = name
        self.age = age
        self.sex = sex
    def __eq__(self, value, /):
        return self.__dict__ == value.__dict__

like = student("like",25,"male")
xue = student("xue",23,"female")
dong = student("like",25,"male")

print(like is xue) #False
print(like is dong) #False
print(like == dong) #True

跳转到最佳答案楼层

suchocolate

参考：https://blog.csdn.net/sinat_38682860/article/details/111315479

isdkz

因为对象的魔法方法 __eq__ 的默认行为也是判断两个对象的地址是否相等，所以 == 和 is 得到的是一样的结果，

如果你要根据属性来判断的话改成这样：

class student(object):
    def __init__(self,name,age,sex):
        self.name = name
        self.age = age
        self.sex = sex
    def __eq__(self, value, /):
        return self.__dict__ == value.__dict__

like = student("like",25,"male")
xue = student("xue",23,"female")
dong = student("like",25,"male")

print(like is xue) #False
print(like is dong) #False
print(like == dong) #True