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[技术交流] 【朱迪的LeetCode刷题笔记】605. Can Place Flowers #Easy #Python

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发表于 2023-6-2 10:37:56 | 显示全部楼层 |阅读模式

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You have a long flowerbed in which some of the plots are planted, and some are not. However, flowers cannot be planted in adjacent plots.

Given an integer array flowerbed containing 0's and 1's, where 0 means empty and 1 means not empty, and an integer n, return true if n new flowers can be planted in the flowerbed without violating the no-adjacent-flowers rule and false otherwise.


Example 1:
Input: flowerbed = [1,0,0,0,1], n = 1
Output: true

Example 2:
Input: flowerbed = [1,0,0,0,1], n = 2
Output: false

Constraints:
1 <= flowerbed.length <= 2 * 104
flowerbed is 0 or 1.
There are no two adjacent flowers in flowerbed.
0 <= n <= flowerbed.length

Judy
Python
  1. class Solution(object):
  2.     def canPlaceFlowers(self, flowerbed, n):
  3.         """
  4.         :type flowerbed: List[int]
  5.         :type n: int
  6.         :rtype: bool
  7.         """
  8.         l = len(flowerbed)
  9.         i = 0
  10.         while i < l:
  11.             if n == 0:
  12.                 return True
  13.             if flowerbed[i] == 0:
  14.                 if i + 1 < l:
  15.                     if flowerbed[i + 1] == 0:
  16.                         n -= 1
  17.                         i += 2
  18.                     else:
  19.                         i += 3
  20.                 else:
  21.                     return n - 1 == 0
  22.             else:
  23.                 i += 2
  24.         
  25.         return n == 0
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https://leetcode.com/problems/ca ... p;envId=leetcode-75
Sol1
Python
  1. class Solution:
  2.     def canPlaceFlowers(self, flowerbed: List[int], n: int) -> bool:
  3.         if n == 0:
  4.             return True
  5.         for i in range(len(flowerbed)):
  6.             if flowerbed[i] == 0 and (i == 0 or flowerbed[i-1] == 0) and (i == len(flowerbed)-1 or flowerbed[i+1] == 0):
  7.                 flowerbed[i] = 1
  8.                 n -= 1
  9.                 if n == 0:
  10.                     return True
  11.         return False
复制代码

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