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[技术交流] 【朱迪的LeetCode刷题笔记】238. Product of Array Except Self #Medium #Python #C++

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发表于 2023-6-3 12:17:03 | 显示全部楼层 |阅读模式

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Given an integer array nums, return an array answer such that answer<i> is equal to the product of all the elements of nums except nums<i>.

The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.

You must write an algorithm that runs in O(n) time and without using the division operation.

Example 1:
Input: nums = [1,2,3,4]
Output: [24,12,8,6]

Example 2:
Input: nums = [-1,1,0,-3,3]
Output: [0,0,9,0,0]

Constraints:
2 <= nums.length <= 105
-30 <= nums<i> <= 30
The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.

Follow up:
Can you solve the problem in O(1) extra space complexity? (The output array does not count as extra space for space complexity analysis.)

Judy
Python
  1. class Solution(object):
  2.     def productExceptSelf(self, nums):
  3.         """
  4.         :type nums: List[int]
  5.         :rtype: List[int]
  6.         """
  7.         a = 1
  8.         b = 1
  9.         l = len(nums)
  10.         answer = []
  11.         for x in nums:
  12.             answer.append(a)
  13.             a *= x
  14.         for i in range(l-1, -1, -1):
  15.             answer[i] *= b
  16.             b *= nums[i]
  17.         return answer
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Mike
C++
  1. vector<int> productExceptSelf(vector<int>& nums) {
  2.         vector<int> result;
  3.         int prod = 1;
  4.         for (auto i : nums) {
  5.             result.push_back(prod);
  6.             prod = i;
  7.         }
  8.         prod = 1;
  9.         for (int i = nums.size() - 1; i >= 0; i--) {
  10.             result[i]= prod;
  11.             prod *= nums[i];
  12.         }
  13.         return result;
  14.     }
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