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键盘上按照年月日的格式输入年份、月和日期,运行程序以后,判断这一天是这一年的第几天。
输入描述
标准输入,输入三个整数,即年、月、日(都是正数),以空格间隔,不保证输入的年份和日期是正确的。
输出描述
标准输出,输出这一天是这一年的第几天,如果日期不合法,输出“data error!”。- #include<stdio.h>
- int main()
- {
- int year,mon,day,days=0;
- scanf("%d%d%d",&year,&mon,&day);
- if(year>9999||year<1000) printf("date error!");
- else
-
- {if(((year%400==0)||(year%34==0&&year%100!=0))&&mon>2)
- days++;
- switch(mon)
- {
- case 1:
- {
- if(day>31) printf("data error!");
- else
- {days=day;printf("%d",days);}
- break;
- }
- case 2:
- {
- if(((year%400==0||(year%4==0||year%100!=0))&&mon>29)||((year%400!=0||(year%4!=0||year%100==0))&&mon>28))printf("data error!");
- else
- {days=day+31;printf("%d",days);}
- break;
- }
- case 3:
- {
- if(day>31) printf("data error!");
- else
- {days=day+59;printf("%d",days);}
- break;
- }
- case 4:
- {
- if(day>30) printf("data error!");
- else
- {days=day+90;printf("%d",days);}
- break;
- }
- case 5:
- {
- if(day>31) printf("data error!");
- else
- {days=day+120;printf("%d",days);}
- break;
- }
- case 6:
- {
- if(day>30) printf("data error!");
- else
- {days=day+151;printf("%d",days);}
- break;
- }
- case 7:
- {
- if(day>31) printf("data error!");
- else
- {days=day+181;printf("%d",days);}
- break;
- }
- case 8:
- {
- if(day>31) printf("data error!");
- else
- {days=day+212;printf("%d",days);}
- break;
- }
- case 9:
- {
- if(day>30) printf("data error!");
- else
- {days=day+243;printf("%d",days);}
- break;
- }
- case 10:
- {
- if(day>31) printf("data error!");
- else
- {days=day+273;printf("%d",days);}
- break;
- }
- case 11:
- {
- if(day>30) printf("data error!");
- else
- {days=day+304;printf("%d",days);}
- break;
- }
- case 12:
- {
- if(day>31) printf("data error!");
- else
- {days=day+334;printf("%d",days);}
- break;
- }
- default:printf("date error!");
- }
- }
- }
复制代码
这段代码有以下问题:
1. 第7行的输出应该是"data error!"而不是"date error!"
2. 第11行的年份除以34应该是除以4
3. 在每个case中都需要加上break语句,否则会继续执行下一个case
4. 在第24行到27行的公式中,应该是闰年的情况下mon>2,而不是mon>29或mon>28
5. 最后的default语句不需要输出任何内容
修改后的代码如下:
- ++
- #include <stdio.h>
- int main() {
- int year, mon, day, days = 0;
- scanf("%d%d%d", &year, &mon, &day);
- if (year > 9999 || year < 1000)
- printf("data error!");
- else {
- if (((year % 400 == 0) || (year % 4 == 0 && year % 100 != 0)) && mon > 2)
- days++;
- switch (mon) {
- case 1: {
- if (day > 31)
- printf("data error!");
- else {
- days = day;
- printf("%d", days);
- }
- break;
- }
- case 2: {
- if ((year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) && day > 29 ||
- (year % 400 != 0 || (year % 4 != 0 || year % 100 == 0)) && day > 28)
- printf("data error!");
- else {
- days = day + 31;
- printf("%d", days);
- }
- break;
- }
- case 3: {
- if (day > 31)
- printf("data error!");
- else {
- days = day + 59;
- printf("%d", days);
- }
- break;
- }
- case 4: {
- if (day > 30)
- printf("data error!");
- else {
- days = day + 90;
- printf("%d", days);
- }
- break;
- }
- case 5: {
- if (day > 31)
- printf("data error!");
- else {
- days = day + 120;
- printf("%d", days);
- }
- break;
- }
- case 6: {
- if (day > 30)
- printf("data error!");
- else {
- days = day + 151;
- printf("%d", days);
- }
- break;
- }
- case 7: {
- if (day > 31)
- printf("data error!");
- else {
- days = day + 181;
- printf("%d", days);
- }
- break;
- }
- case 8: {
- if (day > 31)
- printf("data error!");
- else {
- days = day + 212;
- printf("%d", days);
- }
- break;
- }
- case 9: {
- if (day > 30)
- printf("data error!");
- else {
- days = day + 243;
- printf("%d", days);
- }
- break;
- }
- case 10: {
- if (day > 31)
- printf("data error!");
- else {
- days = day + 273;
- printf("%d", days);
- }
- break;
- }
- case 11: {
- if (day > 30)
- printf("data error!");
- else {
- days = day + 304;
- printf("%d", days);
- }
- break;
- }
- case 12: {
- if (day > 31)
- printf("data error!");
- else {
- days = day + 334;
- printf("%d", days);
- }
- break;
- }
- default:
- printf("data error!");
- break;
- }
- }
- return 0;
- }
复制代码
球一个最佳答案谢谢啦!这对我非常重要!  
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