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这个月份算出来是15,哪里出错了。
以下是计算月份的代码void calculate_mouth(int time_s,int *mouth)
{
int mouth_all[] = {31,28,31,30,31,30,31,31,30,31,30,31};
int day_remainder = (time_s % (3 * 365 * 86400 + 366 * 86400)) / 86400;//get the remainder day of four year
if (day_remainder >= 365 * 2 + 366)
{
mouth_all[1] = 29;
}
int day;
calculate_day(time_s,&day);
int i;
for (i = 0;i < 12;i++)
{
int n = day - mouth_all[i];
if (n > 0)
{
continue;
}
else
{
*mouth = i + 1;
break;
}
}
}
以下是完整代码#include <stdio.h>
#include <time.h>
void leap_years(int time_s,int *leap)
{
int day_remainder = (time_s % (3 * 365 * 86400 + 366 * 86400)) / 86400;//get the remainder day of four year
if (day_remainder >= 0 && day_remainder < 365)
{
*leap = 0;
}
else if (day_remainder >= 365 && day_remainder < (365 * 2))
{
*leap = 1;
}
else if (day_remainder >= (365 * 2) && day_remainder < (365 * 2 + 366))
{
*leap = 2;
}
else
{
*leap = 3;
}
}
void cal_second_remainder(int time_s,int *second_remainder)
{
int leap;
leap_years(time_s,&leap);
switch(leap)
{
case 0:*second_remainder = time_s % (3 * 365 * 86400 + 366 * 86400);break;
case 1:*second_remainder = time_s % (3 * 365 * 86400 + 366 * 86400) - 365 * 86400;break;
case 2:*second_remainder = time_s % (3 * 365 * 86400 + 366 * 86400) - 365 * 2 * 86400;break;
case 3:*second_remainder = time_s % (3 * 365 * 86400 + 366 * 86400) - (365 * 2 + 366) * 86400;break;
}
}
void calculate_year(int time_s,int *year)
{
int leap;
leap_years(time_s,&leap);
*year = 4 * (time_s / (3 * 365 * 86400 + 366 * 86400)) + 1970 + leap;
}
void calculate_day(int time_s,int *day)
{
int second_remainder;
cal_second_remainder(time_s,&second_remainder);
*day = second_remainder / (24 * 60 * 60);
}
void calculate_hour_minute(int time_s,int *hour,int *minute)
{
int day,second_remainder,second;
calculate_day(time_s,&day);
cal_second_remainder(time_s,&second_remainder);
second = second_remainder - day * 24 * 60 * 60;
*hour = second / (60 * 60);
*minute = (second % (60 * 60)) / 60;
}
void calculate_mouth(int time_s,int *mouth)
{
int mouth_all[] = {31,28,31,30,31,30,31,31,30,31,30,31};
int day_remainder = (time_s % (3 * 365 * 86400 + 366 * 86400)) / 86400;//get the remainder day of four year
if (day_remainder >= 365 * 2 + 366)
{
mouth_all[1] = 29;
}
int day;
calculate_day(time_s,&day);
int i;
for (i = 0;i < 12;i++)
{
int n = day - mouth_all[i];
if (n > 0)
{
continue;
}
else
{
*mouth = i + 1;
break;
}
}
}
int prnitf_time(int time_s,int year,int day,int hour,int minute)
{
printf("senconds:%i\n",time_s);
printf("year:%i\n",year);
printf("day:%i\n",day);
printf("hour:%i\n",hour);
printf("minute:%i\n",minute);
}
int main()
{
int time_s = time(NULL) + 8 * 60 * 60;
int year,day,hour,minute,mouth;
calculate_year(time_s,&year);
calculate_day(time_s,&day);
calculate_hour_minute(time_s,&hour,&minute);
calculate_mouth(time_s,&mouth);
prnitf_time(time_s,year,day,hour,minute);
printf("%i",mouth);
return 0;
}
在代码中,你定义了一个名为`mouth_all`的数组,并尝试将初始值赋给它。然而,你使用了错误的语法来初始化数组。正确的写法是使用大括号`{}`来赋值,而不是使用等号`=`。以下是修改后的代码: int month_all[] = {31,28,31,30,31,30,31,31,30,31,30,31};
另外,在循环中,你需要更新`day`的值,以便计算剩余天数。你可以通过减去已经过去的月份的天数来实现。以下是修改后的`calculate_mouth`函数的完整代码: void calculate_mouth(int time_s,int *mouth){ int month_all[] = {31,28,31,30,31,30,31,31,30,31,30,31}; // 修改了语法错误 int day_remainder = (time_s % (3 * 365 * 86400 + 366 * 86400)) / 86400; // 获取四年的余下天数 if (day_remainder >= 365 * 2 + 366) { month_all[1] = 29; // 修改了变量名错误 } int day; calculate_day(time_s,&day); int i; for (i = 0; i < 12; i++) { day -= month_all[i]; // 更新剩余天数 if (day <= 0) // 找到月份后立即停止循环 { *mouth = i + 1; break; } }}
通过以上修改,你应该能够正确计算出月份。希望对你有所帮助!
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