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本帖最后由 yg飞许 于 2024-1-22 20:58 编辑
为什,1~36对角和是222,改成720
求1~49对角线和,
下面只能求25对角线和,
- #include <stdio.h>
- #include <math.h>
- main(){
- int num;
- printf("请输入一个整数:");
- scanf("%d",&num);
- int row=sqrt(num);
-
- int arr[row][row],times = 1,sum1 = 0,sum2 = 0;
- for(int i = 0;i<=row-1;i++){
- for(int j = 0;j<=row-1;j++){
- arr[i][j] = times;
- times = times + 1;
- if(i==j){
- sum1 = sum1 + arr[i][j];
- }
-
-
- //arr[i][j] = i * 5 + j+1;
- }
- }
- printf("{") ;
- for(int i = 0;i<=row-1;i++){
- printf("{");
- for(int j = 0;j<=row-1;j++){
- if(i + j == row-1){
- sum2 = sum2 + arr[i][j];
- }
- if(j==row-1){
- printf("%d",arr[i][j]);
- break;//continue
- }
- printf("%d,",arr[i][j]);
- }
- printf("},");
- printf("\n");
- }
- printf("}\n");
- printf("两条对角线之和为%d",sum1 + sum2);
- }
复制代码
- #include <stdio.h>
- #include <math.h>
- int main(){
- int num, sum1 = 0, sum2 = 0;
- int row, i, j, count = 1;
- printf("please input number you want to caculate:");
- scanf("%d",&num);
- row = sqrt(num);
- int array[row][row];
- for (i = 0; i < row; i++){
- for (j = 0; j < row; j++){
- array[i][j] = count++;
- if (i == j){
- sum1 += array[i][j];
- }
- if ((i + j) == row - 1){
- sum2 += array[i][j];
- }
- }
- }
- printf("sum is %d.\n",sum1+sum2);
- return 0;
- }
复制代码
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