为啥call s == call offset s?

疯狂的一家

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[backcolor=initial !important] [backcolor=white !important]assume cs:codesg, ds:datasg, ss:stacksg [backcolor=white !important]datasg segment [backcolor=white !important]    dw 0 [backcolor=white !important]datasg ends [backcolor=white !important]stacksg segment [backcolor=white !important]    dw 16 dup(0) [backcolor=white !important]stacksg ends [backcolor=white !important]codesg segment [backcolor=white !important]start: [backcolor=white !important]    mov ax, datasg [backcolor=white !important]    mov ds, ax [backcolor=white !important]      [backcolor=white !important]    mov bx, 0 [backcolor=white !important]    call s [backcolor=white !important]s: [backcolor=white !important]    mov ax, 2 [backcolor=white !important]    mov ax, 4c00h [backcolor=white !important]    int 21h [backcolor=white !important]codesg ends [backcolor=white !important]end start

它的机器指令是
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[backcolor=initial !important] [backcolor=white !important]-u [backcolor=white !important]14A0:0000 B89D14        MOV     AX,149D [backcolor=white !important]14A0:0003 8ED8          MOV     DS,AX [backcolor=white !important]14A0:0005 BB0000        MOV     BX,0000 [backcolor=white !important]14A0:0008 E80000        CALL    000B [backcolor=white !important]14A0:000B B80200        MOV     AX,0002 [backcolor=white !important]14A0:000E B8004C        MOV     AX,4C00 [backcolor=white !important]14A0:0011 CD21          INT     21

而[backcolor=white !important][size=1em]

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[backcolor=initial !important] [backcolor=white !important]assume cs:codesg, ds:datasg, ss:stacksg [backcolor=white !important]datasg segment [backcolor=white !important]    dw 0 [backcolor=white !important]datasg ends [backcolor=white !important]stacksg segment [backcolor=white !important]    dw 16 dup(0) [backcolor=white !important]stacksg ends [backcolor=white !important]codesg segment [backcolor=white !important]start: [backcolor=white !important]    mov ax, datasg [backcolor=white !important]    mov ds, ax [backcolor=white !important]      [backcolor=white !important]    mov bx, 0 [backcolor=white !important]    call offset s [backcolor=white !important]s: [backcolor=white !important]    mov ax, 2 [backcolor=white !important]    mov ax, 4c00h [backcolor=white !important]    int 21h [backcolor=white !important]codesg ends [backcolor=white !important]end start

编译结果
D:\asm\prj>ml 35.asm
Microsoft (R) Macro Assembler Version 6.15.8803
Copyright (C) Microsoft Corp 1981-2000.  All rights reserved.

Assembling: 35.asm

Microsoft (R) Segmented Executable Linker  Version 5.60.339 Dec  5 1994
Copyright (C) Microsoft Corp 1984-1993.  All rights reserved.

Object Modules [.obj]: 35.obj
Run File [35.exe]: "35.exe"
List File [nul.map]: NUL
Libraries [.lib]:
Definitions File [nul.def]:
LINK : warning L4021: no stack segment


它的机器指令是
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[backcolor=initial !important] [backcolor=white !important]14A0:0000 B89D14        MOV     AX,149D [backcolor=white !important]14A0:0003 8ED8          MOV     DS,AX [backcolor=white !important]14A0:0005 BB0000        MOV     BX,0000 [backcolor=white !important]14A0:0008 E80000        CALL    000B [backcolor=white !important]14A0:000B B80200        MOV     AX,0002 [backcolor=white !important]14A0:000E B8004C        MOV     AX,4C00 [backcolor=white !important]14A0:0011 CD21          INT     21

本以为call offset s会跳到此指令下一条的IP+offset s(s到ip=0的编移)去,但是从结果看是跳到此指令下一条+到s的编移地址
同时还发现jmp s与jmp offset s的机器指令一样~.

疯狂的一家

完了 变乱码了~~~~~~~~~~~~~~~~

问题就是为啥call s与call offset s的机器指令一样~~~~~~~~~~~~