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发表于 2024-4-30 16:02:57
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非常抱歉,我可能之前漏回答了您的问题。确实,在24点游戏中添加小括号可以增加更多的组合和变化,但是会增加一定的复杂度。
如果要在表达式中添加小括号,可以使用递归函数来尝试不同的括号组合。下面是一个示例代码:
- def add_parentheses(expression, depth):
- if depth == 0:
- return expression
- parentheses_expressions = []
-
- for i in range(1, len(expression) - depth, 2):
- sub_expression = expression[i-1:i+2]
- sub_result = eval(sub_expression)
-
- if isinstance(sub_result, int) and sub_result != 0:
- remaining_expression = expression[:i-1] + expression[i+2:]
- sub_expressions = add_parentheses(remaining_expression, depth - 1)
-
- for sub_expr in sub_expressions:
- parentheses_expressions.append(expression[:i-1] + "(" + sub_expression + ")" + sub_expr)
-
- return parentheses_expressions
- def generate_expressions(numbers, operators, num_parentheses):
- expressions = []
-
- combinations = itertools.product(operators, repeat=3)
- number_perms = list(itertools.permutations(numbers))
-
- for ops in combinations:
- for num_perm in number_perms:
- expression = "{}{}{}{}{}{}{}".format(num_perm[0], ops[0], num_perm[1], ops[1], num_perm[2], ops[2], num_perm[3])
- expressions.append(expression)
-
- expressions_with_parentheses = []
-
- for expr in expressions:
- expressions_with_parentheses.extend(add_parentheses(expr, num_parentheses))
-
- return expressions_with_parentheses
- numbers = [2, 2, 5, 8]
- operators = ['+', '-', '*', '/']
- num_parentheses = 1
- expressions = generate_expressions(numbers, operators, num_parentheses)
- for expr in expressions:
- result = eval(expr)
- if isinstance(result, int) and result > 10 and result % 24 == 0:
- print(expr)
复制代码
这段代码将根据给定的数字、运算符和括号数量生成所有可能的表达式,并输出计算结果为整数且大于10且能被24整除的表达式。
希望这次能解决您的问题。如有其他疑问,请随时提问!
以上回复来自 FishC AI 小助理,如未能正确解答您的问题,请继续追问。 |
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