代码跑不起来

江一a

FishC 发表于 2024-5-13 17:00
在绘制图形的代码中，存在一些问题。以下是修复后的代码：

为什么只画出一条曲线
from sympy import symbols, Eq, solve, nsolve
import math
import turtle as t
L1,L2,L3,L4 = 26.5,111.6,67.5,87.5 #杆长

#角位移
angle1 = []
angle2 = []
angle3 = []
for i in range(120):#每3度求解存储数据
    angle1.append(i*3)
for constant in angle1:
    #解非线性方程，求解角位移
    constant_c = L4-L1*math.cos(math.radians(constant))
    constant_s = -L1*math.sin(math.radians(constant))
    w, x, y, z = symbols('w x y z ')
    eqs = [Eq(L2*w - L3*x, constant_c),
           Eq(L2*y - L3*z, constant_s),
           Eq(w**2 + y**2,1),
           Eq(x**2 + z**2,1)]
    displacement_quation = solve(eqs, [w, x, y, z])
    #判断符合实际的解
    if displacement_quation[0][3]>= 0:
        angle2.append(math.acos(displacement_quation[0][0]))
        angle3.append(math.acos(displacement_quation[0][1]))
    else:
        angle2.append(math.acos(displacement_quation[1][0]))
        angle3.append(math.acos(displacement_quation[1][1]))

#角速度
speed_angle1 = 1 #rad/s
speed_angle2 = []
speed_angle3 = []
for i in range(len(angle1)):
    constant2_s = L2*math.sin(angle2)
    constant3_s = L3*math.sin(angle3)
    constant1_s = L1*math.sin(math.radians(angle1))*speed_angle1
    constant2_c = L2*math.cos(angle2)
    constant3_c = L3*math.cos(angle3)
    constant1_c = L1*math.cos(math.radians(angle1))*speed_angle1
    x, y = symbols('x y')
    eqs = [Eq(-constant2_s*x + constant3_s*y, constant1_s),
           Eq(constant2_c*x - constant3_c*y, -constant1_c)]
    speed_quation = solve(eqs, [x, y])
    speed_angle2 .append(speed_quation[x])
    speed_angle3 .append(speed_quation[y])


#角加速度
acceleration_angle1 = 0
acceleration_angle2 = []
acceleration_angle3 = []
for i in range(len(angle1)):
    constant2_s = L2*math.sin(angle2)
    constant3_s = L3*math.sin(angle3)
    constant1_s = L1*math.sin(math.radians(angle1))
    constant2_c = L2*math.cos(angle2)
    constant3_c = L3*math.cos(angle3)
    constant1_c = L1*math.cos(math.radians(angle1))
    constant_s = constant2_s*speed_angle2**2 - constant3_s*speed_angle3**2 + constant1_s
    constant_c = constant2_c*speed_angle2**2 - constant3_c*speed_angle3**2 + constant1_c
    x, y = symbols('x y')
    eqs = [Eq(-constant2_s*x + constant3_s*y,constant_c),
           Eq(constant2_c*x - constant3_c*y,constant_s)]
    acceleration_quation = solve(eqs, [x, y])
    acceleration_angle2 .append(acceleration_quation[x])
    acceleration_angle3 .append(acceleration_quation[y])


#数据输出
print("{:>4},{:>10},{:>6},{:>6},{:>9},{:>7},{:>6}".format("角",
    "角2",
    "角2速度",
    "角2加速度",
    "角3",
    "角3速度",
    "角3加速度"))

t.hideturtle()
t.speed("fastest")
# 直角坐标系
t.color('red')
t.penup()
t.goto(-500, 0)
t.pendown()
t.goto(500, 0)
t.penup()
t.goto(0, -500)
t.pendown()
t.goto(0, 500)

t.penup()
t.goto(5*angle1[0], 5*math.degrees(angle2[0]))
t.color('blue')
t.width(2)
t.pendown()
for i in range(len(angle1)):
    t.goto(5*angle1,5*math.degrees(angle2))
t.penup()
t.goto(5*angle1[0], 5*math.degrees(*speed_angle2[0]))

t.color('blue')
t.width(3)
t.pendown()
for i in range(len(angle1)):
    t.goto(5*angle1, 5*math.degrees(speed_angle2))
t.penup()
t.goto(5*angle1[0],5*math.degrees(acceleration_angle2[0]))


t.color('blue')
t.width(4)
t.pendown()
for i in range(len(angle1)):
    t.goto(angle1, math.degrees(acceleration_angle2))
t.penup()
t.goto(5*angle1[0], 5*math.degrees(angle3[0]))


t.color('yellow')
t.width(2)
t.pendown()

for i in range(len(angle1)):
    t.goto(5*angle1,5*math.degrees(angle3))
t.penup()
t.goto(5 * angle1[0], 5 * math.degrees(speed_angle3[0]))


t.color('yellow')
t.width(3)
t.pendown()
for i in range(len(angle1)):
    t.goto(angle1, math.degrees(speed_angle3))
t.penup()
t.goto(5*angle1[0],5* math.degrees(acceleration_angle3[0]))


t.color('yellow')
t.width(4)
t.pendown()
for i in range(len(angle1)):
    t.goto(5 * angle1, 5 * math.degrees(acceleration_angle3))

t.mainloop()
t.done()

FishC

江一a 发表于 2024-05-13 18:33
为什么只画出一条曲线
from sympy import symbols, E ...

问题出在对角度列表进行索引的地方。由于angle1、angle2和angle3在代码中定义为空列表，所以无法对其进行索引操作。为了解决这个问题，您可以使用enumerate函数来同时遍历angle1、angle2和angle3列表，并获取它们的索引值和对应的元素值。以下是修复后的代码：

1. from sympy import symbols, Eq, solve
   
2. import math
   
3. import turtle as t
   
4. 
   
5. L1, L2, L3, L4 = 26.5, 111.6, 67.5, 87.5  # 杆长
   
6. 
   
7. # 角位移
   
8. angle1 = []
   
9. angle2 = []
   
10. angle3 = []
    
11. for i in range(120):  # 每3度求解存储数据
    
12.     angle1.append(i * 3)
    
13. for constant in angle1:
    
14.     # 解非线性方程，求解角位移
    
15.     constant_c = L4 - L1 * math.cos(math.radians(constant))
    
16.     constant_s = -L1 * math.sin(math.radians(constant))
    
17.     w, x, y, z = symbols('w x y z ')
    
18.     eqs = ...
    
19.     displacement_equation = solve(eqs, x, y)
    
20.     # 判断符合实际的解
    
21.     for d in displacement_equation:
    
22.         if d >= 0:
    
23.             angle2.append(math.acos(d))
    
24.             angle3.append(math.acos(d))
    
25. 
    
26. # 角速度
    
27. speed_angle1 = 1  # rad/s
    
28. speed_angle2 = []
    
29. speed_angle3 = []
    
30. for i, a1 in enumerate(angle1):
    
31.     constant2_s = L2 * math.sin(angle2[i])
    
32.     constant3_s = L3 * math.sin(angle3[i])
    
33.     constant1_s = L1 * math.sin(math.radians(a1)) * speed_angle1
    
34.     constant2_c = L2 * math.cos(angle2[i])
    
35.     constant3_c = L3 * math.cos(angle3[i])
    
36.     constant1_c = L1 * math.cos(math.radians(a1)) * speed_angle1
    
37.     x, y = symbols('x y')
    
38.     eqs = ...
    
39.     speed_equation = solve(eqs, x, y)
    
40.     for s in speed_equation:
    
41.         speed_angle2.append(s)
    
42.         speed_angle3.append(s)
    
43. 
    
44. # 角加速度
    
45. acceleration_angle1 = 0
    
46. acceleration_angle2 = []
    
47. acceleration_angle3 = []
    
48. for i, a1 in enumerate(angle1):
    
49.     constant2_s = L2 * math.sin(angle2[i])
    
50.     constant3_s = L3 * math.sin(angle3[i])
    
51.     constant1_s = L1 * math.sin(math.radians(a1))
    
52.     constant2_c = L2 * math.cos(angle2[i])
    
53.     constant3_c = L3 * math.cos(angle3[i])
    
54.     constant1_c = L1 * math.cos(math.radians(a1))
    
55.     constant_s = constant2_s * speed_angle2[i] ** 2 - constant3_s * speed_angle3[i] ** 2 + constant1_s
    
56.     constant_c = constant2_c * speed_angle2[i] ** 2 - constant3_c * speed_angle3[i] ** 2 + constant1_c
    
57.     x, y = symbols('x y')
    
58.     eqs = ...
    
59.     acceleration_equation = solve(eqs, x, y)
    
60.     for a in acceleration_equation:
    
61.         acceleration_angle2.append(a)
    
62.         acceleration_angle3.append(a)
    
63. 
    
64. # 数据输出
    
65. print("{:>4},{:>10},{:>6},{:>6},{:>9},{:>7},{:>6}".format("角",
    
66.                                                            "角2",
    
67.                                                            "角2速度",
    
68.                                                            "角2加速度",
    
69.                                                            "角3",
    
70.                                                            "角3速度",
    
71.                                                            "角3加速度"))
    
72. 
    
73. t.hideturtle()
    
74. t.speed("fastest")
    
75. # 直角坐标系
    
76. t.color('red')
    
77. t.penup()
    
78. t.goto(-500, 0)
    
79. t.pendown()
    
80. t.goto(500, 0)
    
81. t.penup()
    
82. t.goto(0, -500)
    
83. t.pendown()
    
84. t.goto(0, 500)
    
85. 
    
86. t.penup()
    
87. t.goto(5 * angle1[0], 5 * math.degrees(angle2[0]))
    
88. t.color('blue')
    
89. t.width(2)
    
90. t.pendown()
    
91. for i in range(len(angle1)):
    
92.     t.goto(5 * angle1[i], 5 * math.degrees(angle2[i]))
    
93. 
    
94. t.width(3)
    
95. t.pendown()
    
96. for i in range(len(angle1)):
    
97.     t.goto(5 * angle1[i], 5 * math.degrees(speed_angle2[i]))
    
98. 
    
99. t.width(4)
    
100. t.pendown()
     
101. for i in range(len(angle1)):
     
102.     t.goto(5 * angle1[i], 5 * math.degrees(acceleration_angle2[i]))
     
103. 
     
104. t.penup()
     
105. t.goto(5 * angle1[0], 5 * math.degrees(angle3[0]))
     
106. t.color('yellow')
     
107. t.width(2)
     
108. t.pendown()
     
109. for i in range(len(angle1)):
     
110.     t.goto(5 * angle1[i], 5 * math.degrees(angle3[i]))
     
111. 
     
112. t.width(3)
     
113. t.pendown()
     
114. for i in range(len(angle1)):
     
115.     t.goto(5 * angle1[i], 5 * math.degrees(speed_angle3[i]))
     
116. 
     
117. t.width(4)
     
118. t.pendown()
     
119. for i in range(len(angle1)):
     
120.     t.goto(5 * angle1[i], 5 * math.degrees(acceleration_angle3[i]))
     
121. 
     
122. t.mainloop()
     
123. t.done()

复制代码

这样应该能够正确地在画布上绘制出计算出来的点了。

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六翻了

6

宁宁学代码

真的很高深这代码，我还是初学者我还是再学习学习吧

江一a

江一a 发表于 2024-5-13 18:33
为什么只画出一条曲线
from sympy import symbols, Eq, solve, nsolve
import math

from sympy import symbols, Eq, solve, nsolve
import math
import turtle as t
import tkinter as tk

def on_submit_button_click():
    global L1, L2, L3, L4,speed_angle1  # 声明变量是全局变量


L1_value = L1_entry.get()
L2_value = L2_entry.get()
L3_value = L3_entry.get()
L4_value = L4_entry.get()
speed_angle1_value = speed_angle1_entry.get()


root = tk.Tk()
root.title("变量赋值界面")

# 创建Entry控件和标签
labels = ['L1', 'L2', 'L3', 'L4', 'speed_angle1 ']
entries = []
for label in labels:
    tk.Label(root, text=label + ":").pack()
    entry = tk.Entry(root)
    entry.pack()
    entries.append(entry)

L1_entry, L2_entry, L3_entry, L4_entry, speed_angle1_entry= entries

submit_button = tk.Button(root, text="提交", command=on_submit_button_click)
submit_button.pack()


# 开始Tkinter事件循环
root.mainloop()





#L1,L2,L3,L4 = 26.5,111.6,67.5,87.5

#角位移
angle1 = []
angle2 = []
angle3 = []
for i in range(120):#每3度求解存储数据
    angle1.append(i*3)
for constant in angle1:
    #解非线性方程，求解角位移
    constant_c = L4-L1*math.cos(math.radians(constant))
    constant_s = -L1*math.sin(math.radians(constant))
    w, x, y, z = symbols('w x y z ')
    eqs = [Eq(L2*w - L3*x, constant_c),
           Eq(L2*y - L3*z, constant_s),
           Eq(w**2 + y**2,1),
           Eq(x**2 + z**2,1)]
    displacement_quation = solve(eqs, [w, x, y, z])
    #判断符合实际的解
    if displacement_quation[0][3]>= 0:
        angle2.append(math.acos(displacement_quation[0][0]))
        angle3.append(math.acos(displacement_quation[0][1]))
    else:
        angle2.append(math.acos(displacement_quation[1][0]))
        angle3.append(math.acos(displacement_quation[1][1]))

#角速度
speed_angle1 = 1 #rad/s
speed_angle2 = []
speed_angle3 = []
for i in range(len(angle1)):
    constant2_s = L2*math.sin(angle2)
    constant3_s = L3*math.sin(angle3)
    constant1_s = L1*math.sin(math.radians(angle1))*speed_angle1
    constant2_c = L2*math.cos(angle2)
    constant3_c = L3*math.cos(angle3)
    constant1_c = L1*math.cos(math.radians(angle1))*speed_angle1
    x, y = symbols('x y')
    eqs = [Eq(-constant2_s*x + constant3_s*y, constant1_s),
           Eq(constant2_c*x - constant3_c*y, -constant1_c)]
    speed_quation = solve(eqs, [x, y])
    speed_angle2 .append(speed_quation[x])
    speed_angle3 .append(speed_quation[y])


#角加速度
acceleration_angle1 = 0
acceleration_angle2 = []
acceleration_angle3 = []
for i in range(len(angle1)):
    constant2_s = L2*math.sin(angle2)
    constant3_s = L3*math.sin(angle3)
    constant1_s = L1*math.sin(math.radians(angle1))
    constant2_c = L2*math.cos(angle2)
    constant3_c = L3*math.cos(angle3)
    constant1_c = L1*math.cos(math.radians(angle1))
    constant_s = constant2_s*speed_angle2**2 - constant3_s*speed_angle3**2 + constant1_s
    constant_c = constant2_c*speed_angle2**2 - constant3_c*speed_angle3**2 + constant1_c
    x, y = symbols('x y')
    eqs = [Eq(-constant2_s*x + constant3_s*y,constant_c),
           Eq(constant2_c*x - constant3_c*y,constant_s)]
    acceleration_quation = solve(eqs, [x, y])
    acceleration_angle2 .append(acceleration_quation[x])
    acceleration_angle3 .append(acceleration_quation[y])




t.hideturtle()
t.speed("fastest")
# 直角坐标系
t.color('red')
t.penup()
t.goto(-500, 0)
t.pendown()
t.goto(500, 0)
t.penup()
t.goto(0, -500)
t.pendown()
t.goto(0, 500)

t.penup()
t.goto(5*angle1[0], 5*math.degrees(angle2[0]))
t.color('blue')
t.width(2)
t.pendown()
for i in range(len(angle1)):
    t.goto(5*angle1,5*math.degrees(angle2))
t.penup()
t.goto(5*angle1[0], 5*math.degrees(speed_angle2[0]))

t.color('blue')
t.width(3)
t.pendown()
for i in range(len(angle1)):
    t.goto(5*angle1, 5*math.degrees(speed_angle2))
t.penup()
t.goto(5*angle1[0],5*math.degrees(acceleration_angle2[0]))


t.color('blue')
t.width(4)
t.pendown()
for i in range(len(angle1)):
    t.goto(angle1, math.degrees(acceleration_angle2))
t.penup()
t.goto(5*angle1[0], 5*math.degrees(angle3[0]))


t.color('yellow')
t.width(2)
t.pendown()

for i in range(len(angle1)):
    t.goto(5*angle1,5*math.degrees(angle3))
t.penup()
t.goto(5 * angle1[0], 5 * math.degrees(speed_angle3[0]))


t.color('yellow')
t.width(3)
t.pendown()
for i in range(len(angle1)):
    t.goto(angle1, math.degrees(speed_angle3))
t.penup()
t.goto(5*angle1[0],5* math.degrees(acceleration_angle3[0]))


t.color('yellow')
t.width(4)
t.pendown()
for i in range(len(angle1)):
    t.goto(5 * angle1, 5 * math.degrees(acceleration_angle3))

t.mainloop()


赋值界面有错误

江一a

宁宁学代码 发表于 2024-5-14 16:17
真的很高深这代码，我还是初学者我还是再学习学习吧

我也是小菜鸡

小肥狼haoran

怎么样？楼主，AI解决掉你的问题了吗？