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本帖最后由 kangels 于 2013-3-19 10:23 编辑 ( ~7 A6 X. ]( u$ U* n
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丢失的类型信息
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9 ~& j7 a, g9 A8 o9 h4 `5 c9 V& J指针变量应该存储两方面的信息：地址，类型信息
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# H/ F/ t1 N/ a" N+ e( T实证
0 z6 ^3 S8 f( D9 E [( p$ \- [2 X用sizeof()，float *,int*,double *....都是4字节没有存储类型信息只有地址信息' f( X$ i2 s( s5 u- j# n' Q
反汇编一段代码来看看
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#include <stdio.h> int gi; int * pi; void main(int argc, char **argv) { pi = &gi; *pi = 12; } 1: #include <stdio.h> 2: int gi; 3: int * pi; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: pi = &gi; 0041138E mov dword ptr ds:[00417140h],417144h 7: *pi = 12; 00411398 mov eax,dword ptr ds:[00417140h] 0041139D mov dword ptr [eax],0Ch 8: } 004113A3 xor eax,eax 004113A5 pop edi 004113A6 pop esi 004113A7 pop ebx 004113A8 mov esp,ebp 004113AA pop ebp 004113AB ret 5 D+ C' O5 V% g4 S. ?% n% S
* E' {; I. S" I9 y实例2：8 u" m% _1 g( u5 Q0 p, i
#include <stdio.h> short gs; short * ps; void main(int argc, char **argv) { ps = &gs; *ps = 12; }
3 \1 L$ _- e% ] 1: #include <stdio.h> 2: short gs; 3: short * ps; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: ps = &gs; 0041138E mov dword ptr ds:[00417140h],417144h 7: *ps = 12; 00411398 mov eax,0Ch 0041139D mov ecx,dword ptr ds:[00417140h] 004113A3 mov word ptr [ecx],ax 8: } 004113A6 xor eax,eax 004113A8 pop edi 004113A9 pop esi 004113AA pop ebx 004113AB mov esp,ebp 004113AD pop ebp 004113AE ret
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实例3：7 T, j. P! D" u y2 e6 d$ N* R3 q
#include <stdio.h> char gc; char * pc; void main(int argc, char **argv) { pc = &gc; *pc = 12; }
+ v& I! o# C( X) { 1: #include <stdio.h> 2: char gc; 3: char * pc; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: pc = &gc; 0041138E mov dword ptr ds:[00417140h],417144h 7: *pc = 12; 00411398 mov eax,dword ptr ds:[00417140h] 0041139D mov byte ptr [eax],0Ch 8: } 004113A0 xor eax,eax 004113A2 pop edi 004113A3 pop esi 004113A4 pop ebx 004113A5 mov esp,ebp 004113A7 pop ebp 004113A8 ret ( Y1 B( M9 q4 P3 V, j8 [
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可以看出指针的类型信息决定了赋值/读取时读/写多少个字节。9 y' C6 o5 p3 T# X, x, U2 {
读/写多少字节的信息不是存放在指针变量中，而是放到了与该地址相关的赋值指令中。6 n3 Y! Y7 N o5 I
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发表于 2013-3-12 20:59:39
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貌似很高深的反汇编
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