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本帖最后由 kangels 于 2013-3-19 10:23 编辑 $ t# w+ S4 s5 }
/ I. J" j# v" e x) F. n7 E丢失的类型信息1 @9 t: b& `; s T) Z
猜测/ g6 @$ V1 K Z0 w7 o8 J
指针变量应该存储两方面的信息：地址，类型信息) R) F% H0 b! R$ s
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实证
* |% X5 q( I/ a) }用sizeof()，float *,int*,double *....都是4字节没有存储类型信息只有地址信息 ~: _$ G# R3 D$ S1 I1 D2 C
反汇编一段代码来看看! y4 r/ p7 I$ ^3 h3 B8 x: t
实例1：9 W' N T% y, {9 T- _
#include <stdio.h> int gi; int * pi; void main(int argc, char **argv) { pi = &gi; *pi = 12; } 1: #include <stdio.h> 2: int gi; 3: int * pi; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: pi = &gi; 0041138E mov dword ptr ds:[00417140h],417144h 7: *pi = 12; 00411398 mov eax,dword ptr ds:[00417140h] 0041139D mov dword ptr [eax],0Ch 8: } 004113A3 xor eax,eax 004113A5 pop edi 004113A6 pop esi 004113A7 pop ebx 004113A8 mov esp,ebp 004113AA pop ebp 004113AB ret & a. \; J+ Z- ~% o0 u, ?, O
& X! v" L# q' q2 M% |+ s- T: W实例2：
. ~" @* j8 }3 h! f$ |* U% G8 q#include <stdio.h> short gs; short * ps; void main(int argc, char **argv) { ps = &gs; *ps = 12; } 5 u7 i: w9 m: O/ I
1: #include <stdio.h> 2: short gs; 3: short * ps; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: ps = &gs; 0041138E mov dword ptr ds:[00417140h],417144h 7: *ps = 12; 00411398 mov eax,0Ch 0041139D mov ecx,dword ptr ds:[00417140h] 004113A3 mov word ptr [ecx],ax 8: } 004113A6 xor eax,eax 004113A8 pop edi 004113A9 pop esi 004113AA pop ebx 004113AB mov esp,ebp 004113AD pop ebp 004113AE ret
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( i( e( K- R( f% O3 g实例3：
) C) K# V1 n) y3 U0 F#include <stdio.h> char gc; char * pc; void main(int argc, char **argv) { pc = &gc; *pc = 12; }
& t2 b$ B5 m! c, p$ u7 Y3 ~ 1: #include <stdio.h> 2: char gc; 3: char * pc; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: pc = &gc; 0041138E mov dword ptr ds:[00417140h],417144h 7: *pc = 12; 00411398 mov eax,dword ptr ds:[00417140h] 0041139D mov byte ptr [eax],0Ch 8: } 004113A0 xor eax,eax 004113A2 pop edi 004113A3 pop esi 004113A4 pop ebx 004113A5 mov esp,ebp 004113A7 pop ebp 004113A8 ret , t" \' ~$ C) q4 I1 T" F% t
" ^, X+ \7 w# M) D$ c" O+ l) c7 i, ?可以看出指针的类型信息决定了赋值/读取时读/写多少个字节。9 X% a* E0 G' _* g% h9 J3 B4 F. L7 L
读/写多少字节的信息不是存放在指针变量中，而是放到了与该地址相关的赋值指令中。
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发表于 2013-3-12 20:59:39
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貌似很高深的反汇编
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