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本帖最后由 kangels 于 2013-3-19 10:23 编辑 ! Z$ B6 J; ^& R3 A) H
- [. [# @5 h @7 l, ?8 X" |0 R丢失的类型信息- n i8 Z( p$ W2 }0 b8 N
猜测
6 J: K, L0 o( {2 P8 p指针变量应该存储两方面的信息：地址，类型信息
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k0 g- U3 m6 f( [7 ?4 M+ A! o7 @实证/ S" n9 n2 g2 G+ d; {' M
用sizeof()，float *,int*,double *....都是4字节没有存储类型信息只有地址信息0 L. {! ]$ T; \7 Z
反汇编一段代码来看看7 ^2 }) W3 |) V$ f
实例1：: c2 E% k7 T/ S( Z
#include <stdio.h> int gi; int * pi; void main(int argc, char **argv) { pi = &gi; *pi = 12; } 1: #include <stdio.h> 2: int gi; 3: int * pi; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: pi = &gi; 0041138E mov dword ptr ds:[00417140h],417144h 7: *pi = 12; 00411398 mov eax,dword ptr ds:[00417140h] 0041139D mov dword ptr [eax],0Ch 8: } 004113A3 xor eax,eax 004113A5 pop edi 004113A6 pop esi 004113A7 pop ebx 004113A8 mov esp,ebp 004113AA pop ebp 004113AB ret * @0 m* G- @# ^" H, c7 u) \( s
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实例2：
1 u+ o" C% h9 D+ J% `7 Y#include <stdio.h> short gs; short * ps; void main(int argc, char **argv) { ps = &gs; *ps = 12; }
7 d3 }; `" v$ } 1: #include <stdio.h> 2: short gs; 3: short * ps; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: ps = &gs; 0041138E mov dword ptr ds:[00417140h],417144h 7: *ps = 12; 00411398 mov eax,0Ch 0041139D mov ecx,dword ptr ds:[00417140h] 004113A3 mov word ptr [ecx],ax 8: } 004113A6 xor eax,eax 004113A8 pop edi 004113A9 pop esi 004113AA pop ebx 004113AB mov esp,ebp 004113AD pop ebp 004113AE ret
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实例3：# Y, J$ U6 Q5 m3 X. r0 ?+ F2 I
#include <stdio.h> char gc; char * pc; void main(int argc, char **argv) { pc = &gc; *pc = 12; }
6 s* _. {8 v6 h. ^% L _ 1: #include <stdio.h> 2: char gc; 3: char * pc; 4: void main(int argc, char **argv) 5: { 00411370 push ebp 00411371 mov ebp,esp 00411373 sub esp,0C0h 00411379 push ebx 0041137A push esi 0041137B push edi 0041137C lea edi,[ebp+FFFFFF40h] 00411382 mov ecx,30h 00411387 mov eax,0CCCCCCCCh 0041138C rep stos dword ptr es:[edi] 6: pc = &gc; 0041138E mov dword ptr ds:[00417140h],417144h 7: *pc = 12; 00411398 mov eax,dword ptr ds:[00417140h] 0041139D mov byte ptr [eax],0Ch 8: } 004113A0 xor eax,eax 004113A2 pop edi 004113A3 pop esi 004113A4 pop ebx 004113A5 mov esp,ebp 004113A7 pop ebp 004113A8 ret
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可以看出指针的类型信息决定了赋值/读取时读/写多少个字节。% p( B8 B1 y3 f. t9 b. q* _
读/写多少字节的信息不是存放在指针变量中，而是放到了与该地址相关的赋值指令中。/ W$ c0 b' H" R3 G+ h% e4 t- l
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发表于 2013-3-12 20:59:39
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貌似很高深的反汇编
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