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悬赏1鱼币已解决
- #include <stdio.h>
- main()
- {
- char c1, c2;
- c1 = 'A' + '8' - '4';
- c2 = 'A' + '8' - 53;
- printf("%c,%dn", c1, c2);
- }
- #define PRICE 30
- main()
- {
- int num,total;
- num=10;
- total=num* PRICE;
- printf(“total=%d”,total);
- }
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最佳答案
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#include //调用标准输出输入头文件
main() //主函数,返回空值
{
char c1, c2; //声明字符c1,c2
c1 = 'A' + '8' - '4'; // c1='A' + '8' - '4'即ASCII码65+56-52即69,对应E
c2 = 'A' + '8' - 53; //c2= 'A' + '8' - 53即ASCII码65+56-53即68
printf("%c,%d\n", c1, c2); //%c即打印c1为字符格式,%d把c2以整型打印
}
#define PRICE 30 //定义PRICE全局变量30,以后若 ...
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