保存为列表形式

xiangjibang

#!/user/bin/python
#-*-coding:UTF-8-*-
a = [[(0, 0)], [(0, 1), (1, 0)], [(2, 0), (1, 1)], [(3, 0), (2, 1)], [(3, 1)], [(0, 3), (4, 0)],
        [(1, 3), (4, 1), (0, 2), (5, 0)], [(1, 2), (5, 1), (2, 3), (6, 0)],[(6, 1), (7, 0), (3, 3), (2, 2)], [(3, 2), (7, 1)], [(8, 0), (4, 3)], [(8, 1), (4, 2), (9, 0), (5, 3)], [(6, 3), (10, 0), (5, 2), (9, 1)], [(11, 0), (7, 3), (6, 2), (10, 1)], [(11, 1), (7, 2)], [(8, 3), (12, 0)], [(9, 3), (12, 1), (8, 2), (13, 0)], [(9, 2), (13, 1), (10, 3), (14, 0)], [(14, 1), (15, 0), (11, 3), (10, 2)],[(11, 2), (15, 1)], [(12, 3)], [(12, 2), (13, 3)], [(14, 3), (13, 2)], [(15, 3), (14, 2)], [(15, 2)]]
for i in range(len(a)) :#出现两次节点编号所在列表E中的索引位置
        if len(a[i]) == 2:
                T = a[i][1]
                print T
        if len(a[i]) == 4:
                F = a[i][1]
                G = a[i][2]
                H = a[i][3]
                print F ,G ,H
输出的结果是：
(1, 0)                     
(1, 1)
(2, 1)
(4, 0)
(7, 1)
(4, 3)
(7, 2)
(12, 0)
(15, 1)
(13, 3)
(13, 2)
(14, 2)
怎么才能使得输出的结果是列表[(1, 0),(1, 1),(2, 1),(4, 0),(7, 1),(4, 3),(7, 2),(12, 0),(15, 1),(13, 3),(13, 2),(14, 2)]。以此类推，谢谢。

wei_Y

啥意思。。

xiangjibang

wei_Y 发表于 2015-3-31 20:49
啥意思。。

就是想让我得出的结果保存在一个列表中。能听懂不？

wei_Y

xiangjibang 发表于 2015-3-31 20:53
就是想让我得出的结果保存在一个列表中。能听懂不？

我是说选哪些保存在列表里。

xiangjibang

wei_Y 发表于 2015-3-31 20:56
我是说选哪些保存在列表里。

(1, 0)                     
(1, 1)
(2, 1)
(4, 0)
(7, 1)
(4, 3)
(7, 2)
(12, 0)
(15, 1)
(13, 3)
(13, 2)
(14, 2)这些保存在列表中

xiangjibang

wei_Y 发表于 2015-3-31 20:56
我是说选哪些保存在列表里。

a = [[(0, 0)], [(0, 1), (1, 0)], [(2, 0), (1, 1)], [(3, 0), (2, 1)], [(3, 1)], [(0, 3), (4, 0)],
        [(1, 3), (4, 1), (0, 2), (5, 0)], [(1, 2), (5, 1), (2, 3), (6, 0)],
    [(6, 1), (7, 0), (3, 3), (2, 2)], [(3, 2), (7, 1)], [(8, 0), (4, 3)], [(8, 1), (4, 2), (9, 0), (5, 3)],
    [(6, 3), (10, 0), (5, 2), (9, 1)], [(11, 0), (7, 3), (6, 2), (10, 1)], [(11, 1), (7, 2)], [(8, 3), (12, 0)],
    [(9, 3), (12, 1), (8, 2), (13, 0)], [(9, 2), (13, 1), (10, 3), (14, 0)], [(14, 1), (15, 0), (11, 3), (10, 2)],
    [(11, 2), (15, 1)], [(12, 3)], [(12, 2), (13, 3)], [(14, 3), (13, 2)], [(15, 3), (14, 2)], [(15, 2)]]
E = [[1, 2, 7, 6], [2, 3, 8, 7], [3, 4, 9, 8], [4, 5, 10, 9], [6, 7, 12, 11], [7, 8, 13, 12], [8, 9, 14, 13],
        [9, 10, 15, 14], [11, 12, 17, 16], [12, 13, 18, 17], [13, 14, 19, 18],[14, 15, 20, 19], [16, 17, 22, 21],
        [17, 18, 23, 22], [18, 19, 24, 23], [19, 20, 25, 24]]
for i in range(len(a)) :#出现两次节点编号所在列表E中的索引位置
        if len(a[i]) == 2:
                T = a[i][1]
                print T
        if len(a[i]) == 4:
                F = a[i][1]
                G = a[i][2]
                H = a[i][3]
                print F ,G ,H
这是我的程序，我现在要将T,F,G,H分别保存在一个列表中。

wei_Y

xiangjibang 发表于 2015-3-31 21:00
a = [[(0, 0)], [(0, 1), (1, 0)], [(2, 0), (1, 1)], [(3, 0), (2, 1)], [(3, 1)], [(0, 3), (4, 0)],
...

我的意思是添加进列表的条件是什么。你写的判断条件是len(a)，列表就是a，一个也判断不上。没有结果。

xiangjibang

wei_Y 发表于 2015-3-31 21:06
我的意思是添加进列表的条件是什么。你写的判断条件是len(a)，列表就是a，一个也判断不上。没有结果。

不知道为什么，复制粘贴上来就乱了。你看看这个图片

wei_Y

1. import itertools
   
2. newlist = [i for i in map(lambda x: x[1:], a) if len(i) == 1 or len(i) == 3]
   
3. print(list(itertools.chain(*newlist)))

复制代码

如果你不介意两层嵌套列表的话可以不用itertools。(想不起来其他办法了。。)

zd0307

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