史上最全的计算机英语资源

上衫夏乡 · 发表于 2017-11-30 22:10:13

谢谢楼主，资源收下了

2399473044 · 发表于 2017-12-1 00:03:59

苯哨野 · 发表于 2017-12-1 14:15:33

为秩序而战，Let the programming to change the world。

lyjlyj · 发表于 2017-12-2 18:43:15

小黑马black · 发表于 2017-12-2 22:12:25

墨梅无锋 · 发表于 2017-12-3 01:41:34

xxw · 发表于 2017-12-5 20:11:06

谢谢分享！！

ド゛゜范 · 发表于 2017-12-6 10:17:19

看一下

fgzhanhao · 发表于 2017-12-7 03:43:19

回复看看！！！！！！！！！！！！

图阿木木 · 发表于 2017-12-9 14:09:37

赞！！

比特阿尔法 · 发表于 2017-12-9 19:55:59

谢谢

sunyu02 · 发表于 2017-12-10 08:38:48

谢谢分享

阳pipi · 发表于 2017-12-11 08:02:06

学习

taibin · 发表于 2017-12-11 23:12:38

我回复过了

ghasb0007 · 发表于 2017-12-12 08:52:43

Ry丶落魄书生 · 发表于 2017-12-12 16:52:21

Notice that the weight of the position to the left of the units position is 8. This is 8 times 1. Then notice that the weight of the next position is 64, or 8 times 8. If another position existed, it would be 64 times 8, or 51 2. To find the weight of the next higher-order position, multiply the weight of the current position by the number base (or 8, in this example). To calculate the weights of position to the right of the radix point, divide by the number base. In the octal system, the position immediately to the fight of the octal point is 1/8, or .125. The next position is .125/8, or .015625, which can also be written as 1/64.

欧大飞 · 发表于 2017-12-12 17:12:23

ahhhhh

CT2004 · 发表于 2017-12-13 08:41:23

谢谢

payton24 · 发表于 2017-12-13 17:49:42

看看，不错的样子哦

Cristinano · 发表于 2017-12-13 18:06:15

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