S1E16：拾遗 | 课后测试题及答案

吖呵来咯

12

开开卡丁车

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ED_smile

100
0次
a,b,c
a=(4,15),b=5,c=15
if a;else b;
if a;sheds=2;else b;
while(score>=0)readin;count++;    stage2;

藏狐

1

颜祖逆袭之路

校对

碱默

小甲鱼yyds

Dorkysom

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priscillafour

0. 10次
1. 10个B
2. a
3. a = 15, b = 4, c = 9
4. z = x < 0 ? -x : x
5.
A:
        if (size > 12)
        {
                cost = cost * 1.05;
                flag = 2;
        }
        bill = cost * flag;
B:
if (ibex > 14)
{
        sheds = 3;
}
sheds = 2;
help = 2 * sheds;
C.
if (score < 0)
{
        printf("count = %d\n", count);
}
count++;
scanf("%d", &score);

动动手：
0. done
#include <stdio.h>
#include <math.h>

int main()
{
    int year;
    float benjin = 10000.00;
    float x, y;
    float x_interest;
    float y_interest;
    float x_rate = 0.10, y_rate = 0.05;

    x = 10000.00, y = 10000.00;
    for (year = 0; x >= y; year ++)
    {
        x = benjin + (benjin * x_rate) * year;
        y = benjin * pow((1+y_rate), year);
        if (y > x)
        {
            break;
        }
    }

    printf("%d年后，黑夜的投资额超过小甲鱼！\n", year);
    printf("小甲鱼的投资额是:%.2f\n", x);
    printf("黑夜的投资额是：%.2f\n", y);



    return 0;
}
1. not sure why dead circle...
#include <stdio.h>
#include <math.h>

int main()
{
    int year;
    double prize = 4000000.00;
    double expense = 500000.00;
    double rate = 0.08;

    for (year = 0; prize > 0; year ++)
    {
        prize = prize - expense;
        if (prize <= 0)
        {
            break;
        }
        else
        {
            prize = prize * pow((1+rate), year);
        }

    }

    printf("%d年后小甲鱼败光了所有的家产，再次回到一贫如洗。\n", year);


    return 0;
}
2. will do
3. will do

鱼子酱?

a

八重神子的狗

0.无数个
1.11
2.a b c
3.a=21
b=10
c=4
4.|x|>0? z=|x|:z!=|x|
5.if(size>12)
{
cost =cost *1.05;
}
bill =cost * flag;

if (ibex >14)
{
sheds =3;
}
sheds = 2;
help = 2*sheds;

redin: scanf("%d",&score);
if(score <0)
{
printf("count =%d\n,count);
}
count++;
goto readin;

LilPan

1

一位有志青年

#include<stdio.h>
#include<math.h>
int main()
{
        int x=0,y=0,year=2;
        while(x>=y)
        {
        x=pow(10000*0.1,year);
        y=pow(10000+10000*0.05,year);
        year++;
        }
        printf("%d年后，黑夜的投资额超过小甲鱼！\n",year);
        printf("小甲鱼的投资额是%.2f",x);
        printf("黑夜的投资额是：%.2f",y);
       
       
       
       
       
       
       
        return 0;
}

1613551

今天又是元气满满的一天呢

壹零玖肆

来啦来啦

dfsldfsl

11

1050293757

真造雷虎

1

fishxuan

20190530

1

loucer

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