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发表于 2019-9-24 00:18:31
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显示全部楼层
0.10个
1.11个
2.a
3.14,5,9
4.Z = X >= 0 ? X : -X ;
5.if(size>12)
{
cost *=1.05;
flag = 2;
}
else
{
bill = cost * flag;
}
if(ibex>14)
{
sheds = 3;
}
else
{
sheds = 2;
help = 2 * sheds;
}
while(1)
{
scanf("%d",&score);
if(score < 0)
{
printf("count = %d\n",count);break;
}
count++;
}
0.#include <stdio.h>
int main()
{
int year;
float all1 = 10000,all2 = 10000;
for(year = 0;all1 >= all2;year++)
{
all1 = 10000 * ( 1 + (year + 1) * 0.1);
all2 = all2 * 1.05;
}
printf("%d年后,黑夜的投资额超过小甲鱼!\n\
小甲鱼的投资额是:%.2f\n\
黑夜的投资额是:%.2f",year,all1,all2);
return 0;
}
1.#include<stdio.h>
int main()
{
float a = 4000000;
int year;
for(year = 0;a>0;year++)
{
a = (a - 500000)*1.08;
}
printf("%d年之后,小甲鱼败光了所有的家产,再次回到一贫如洗\n",year);
return 0;
}
2.#include<stdio.h>
#include<math.h>
int main()
{
float pi = 0,temp = 1,i;
for(i = -1;temp > 0.00000001;)
{
i = -i;
pi = pi + 1/i;
i = i>0?i+2:i-2;
temp = i>0? 1/i :-1/i;
}
printf("π的值约为%.7f",4*pi);
return 0;
}
3.#include<stdio.h>
int main()
{
int month,sum = 1;
int a[25];
a[0]=2;
a[1]=3;
for(month = 2;month <=23;month++)
{
sum = a[month-2]*2 + (a[month-1]-a[month-2]);
a[month] = sum;
}
printf("两年后共有%d只兔子。",sum);
return 0;
}
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