|
发表于 2020-4-3 13:36:48
|
显示全部楼层
测试题:
0.100次;
1.0;
2. c=5;b=c;a=b;
3.a=15;b=4; c=15;
4.z=x>0?x:-x ;
5.
A:
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
B:
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
help = 2 * sheds;
}
C:
if (score < 0)
{
printf("count = %d\n", count);
}
else
{
count++;
scanf("%d", &score);
}
动动手:
0.代码如下:
#include <stdio.h>
int main()
{
int i=1;
float sjy;
float shy=10000;
while(1)
{
shy=shy*1.05;
sjy=(i*0.1+1)*10000;
if(shy>=sjy)
{
printf("在第%d年黑夜超过小甲鱼\n",i);
break;
}
printf("正在计算,i==%d年\n",i);
i=i+1;
}
return 0;
}
1.代码如下:
#include <stdio.h>
int main()
{
float sum=400;
int i=1;
while(1)
{
sum=(sum-50)*(0.08+1);
if(sum<=0)
{
printf("%d年后,小甲鱼重新一贫如洗",i);
break;
}
i=i+1;
}
return 0;
}
2.代码如下:
#include <stdio.h>
#include <math.h>
int main()
{
double sum=0;
double i;
double m;
int j;
j=1;
for(i=1.0000000000,j=1;i<100000000;j++)
{
m=fabs(1.0000000000/i);
if(j%2==0)
{
m=-m;
}
sum=sum+m;
printf("%.10f,%.10f,%d,%.10f\n",i,m,j,sum);
i=i+2.0000000000;
}
sum=sum*4.0000000000;
printf("PI的值约为~~%.7f",sum);
return 0;
}
3.代码如下:
#include <stdio.h>
int main()
{
int a=0;
int b=1;
int t;
int i;
for(i=1;i<=24;i++)
{
printf("Fibonacci数列的值依次为:%d月份 %d对\n",i,b);
t=a+b;
a=b;
b=t;
}
return 0;
}
|
|