含j的运算是怎么算的

Emily-CS

1. <li class="alt"><span><span>>>>divmod(</span><span class="number">1</span><span>,</span><span class="number">2</span><span>)  </span></span></li><li class=""><span>(<span class="number">0</span><span>,</span><span class="number">1</span><span>)  </span></span></li><li class="alt"><span>>>>divmod(<span class="number">3.14159</span><span>,</span><span class="number">1.5</span><span>)  </span></span></li><li class=""><span>(<span class="number">2.0</span><span>,</span><span class="number">0.4159000000000002</span><span>)  </span></span></li><li class="alt"><span>>>><span class="number">5</span><span>+</span><span class="number">6j</span><span>//</span><span class="number">3</span><span>+</span><span class="number">2j</span><span>  </span></span></li><li class=""><span><span class="number">2</span><span>+</span><span class="number">0j</span><span>  </span></span></li><li class="alt"><span>>>><span class="number">5</span><span>+</span><span class="number">6j</span><span>%</span><span class="number">3</span><span>+</span><span class="number">2j</span><span>  </span></span></li><li class=""><span>-<span class="number">1</span><span>+</span><span class="number">2j</span><span>  </span></span></li><li class="alt"><span>>>>divmod(<span class="number">5</span><span>+</span><span class="number">6j</span><span>,</span><span class="number">3</span><span>+</span><span class="number">2j</span><span>)  </span></span></li><li class=""><span>((<span class="number">2</span><span>+</span><span class="number">0j</span><span>),(-</span><span class="number">1</span><span>+</span><span class="number">2j</span><span>))  </span></span></li>

复制代码

其中含有j的部分的除法，乘法，取余是怎么算的呢？

Emily-CS

>>>divmod(1,2)  
(0,1)  
>>>divmod(3.14159,1.5)  
(2.0,0.4159000000000002)  
>>>5+6j//3+2j  
2+0j  
>>>5+6j%3+2j  
-1+2j  
>>>divmod(5+6j,3+2j)  
((2+0j),(-1+2j))  

代码如此

爱，不解释

你这也太杂乱了

sinzero

不知道这个复数除法有什么意义。。。
大概余数标准是模最小，所以有负数。