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突然感觉难好多啊,4个def某块 啥意思,始终绕不过来 都开始朱行翻译了
- import os
- def print_pos(key_dict): #def 创建函数名(参数)
- keys = key_dict.keys() #返回字典中键列表 (key1:value1,key2:wallet) 键必须唯一,值不必
- keys = sorted(keys) # 由于字典是无序的,我们这里对行数进行排序
- for each_key in keys:
- print('关键字出现在第 %s 行,第 %s 个位置。' % (each_key, str(key_dict[each_key])))
- def pos_in_line(line, key):
- pos = []
- begin = line.find(key) # find查找key 有 !=0.找不到返回-1
- while begin != -1:
- pos.append(begin + 1) # 用户的角度是从1开始数,append是 在列表添加这个新元素
- begin = line.find(key, begin+1) # 从下一个位置继续查找
- return pos # 返回到pos
- def search_in_file(file_name, key): #file 文件
- f = open(file_name)
- count = 0 # 记录行数
- key_dict = dict() # 字典,用户存放key所在具体行数对应具体位置
-
- for each_line in f:
- count += 1
- if key in each_line:
- pos = pos_in_line(each_line, key) # key在每行对应的位置
- key_dict[count] = pos
-
- f.close()
- return key_dict
- def search_files(key, detail):
- all_files = os.walk(os.getcwd()) #walk 返回三元组(路径目录文件名)
- txt_files = []
- for i in all_files:
- for each_file in i[2]:
- if os.path.splitext(each_file)[1] == '.txt': # 根据后缀判断是否文本文件 split分离wen'j文件扩展
- each_file = os.path.join(i[0], each_file) #join 将合并成路径名
- txt_files.append(each_file)
- for each_txt_file in txt_files:
- key_dict = search_in_file(each_txt_file, key)
- if key_dict:
- print('================================================================')
- print('在文件【%s】中找到关键字【%s】' % (each_txt_file, key))
- if detail in ['YES', 'Yes', 'yes']:
- print_pos(key_dict)
- key = input('请将该脚本放于待查找的文件夹内,请输入关键字:')
- detail = input('请问是否需要打印关键字【%s】在文件中的具体位置(YES/NO):' % key)
- search_files(key, detail)
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