[已解决]如何删除list中指定的元素

fzp8656342

如何删除list中指定的元素?

word = ['+1\tThis book is such a life saver.  It has been so helpful to be able to go back to track trends, answer pediatrician questions, or communicate with each other when you are up at different times of the night with a newborn.  I think it is one of those things that everyone should be required to have before they leave the hospital.  We went through all the pages of the newborn version, then moved to the infant version, and will finish up the second infant book (third total) right as our baby turns 1.  See other things that are must haves for baby at [...]\n', '+1\tI bought this a few times for my older son and have bought it again for my newborn. This is super easy to use and helps me keep track of his daily routine. When he started going to the sitter when I went back to work, it helped me know how his day went to better prepare me for how the evening would most likely go. When he was sick, it help me keep track of how many diapers a day he was producing to make sure he was getting dehydrated. The note sections to the side and bottom are useful too because his sitter writes in small notes about whether or not he liked his lunch or if the playtime included going for a walk, etc.Excellent for moms who are wanting to keep track of their kids daily routine even though they are at work. Excellent for dads to keep track as my husband can quickly forget what time he fed our son. LOL\n', '+1\tThis is great for basics, but I wish the space to write things in was bigger. A lot times I need struggle trying to read what the caretaker wrote in because the spaces go together.\n']

如何删除  'is'

使word里面不再有'is' 这个单词?

最佳答案

月排行榜 / 总排行榜

冬雪雪冬

2017-2-4 08:32:29

实际上列表中是3个长字符串，即3个元素，而这3个元素都不是'is'，'is'是在字符串中的子字符串，需要对每个字符串做替换操作，一条语句就OK了，用' is '而不是'is'是为了仅把单词去掉，而像this中的is就不去掉了。

1. word = [i.replace(' is ', ' ') for i in word]

复制代码

跳转到最佳答案楼层

冬雪雪冬

实际上列表中是3个长字符串，即3个元素，而这3个元素都不是'is'，'is'是在字符串中的子字符串，需要对每个字符串做替换操作，一条语句就OK了，用' is '而不是'is'是为了仅把单词去掉，而像this中的is就不去掉了。

1. word = [i.replace(' is ', ' ') for i in word]

复制代码

新手·ing

表示我只知道语法
用     del

fzp8656342

word[0].split()
b = []
for i in range(len(a)):
    if a[i] != 'is':
        b.append(a[i])
b




先把word里的单词split成一个个字符串,然后再建立一个新的列表,每个word里面的元素判断是否是'is'如果是的话就不放进新的列表,如果不是的话就放进新的列表

b
Out[92]:
['+1',
'This',
'book',
'such',
'a',
'life',
'saver.',
'It',
'has',
'been',
'so',
'helpful',
'to',
'be',
'able',
'to',
'go',
'back',
'to',
'track',
'trends,',
'answer',
'pediatrician',
'questions,',
'or',
'communicate',
'with',
'each',
'other',
'when',
'you',
'are',
'up',
'at',
'different',
'times',
'of',
'the',
'night',
'with',
'a',
'newborn.',
'I',
'think',
'it',
'one',
'of',
'those',
'things',
'that',
'everyone',
'should',
'be',
'required',
'to',
'have',
'before',
'they',
'leave',
'the',
'hospital.',
'We',
'went',
'through',
'all',
'the',
'pages',
'of',
'the',
'newborn',
'version,',
'then',
'moved',
'to',
'the',
'infant',
'version,',
'and',
'will',
'finish',
'up',
'the',
'second',
'infant',
'book',
'(third',
'total)',
'right',
'as',
'our',
'baby',
'turns',
'1.',
'See',
'other',
'things',
'that',
'are',
'must',
'haves',
'for',
'baby',
'at',
'[...]']